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ZanzabumX [31]
3 years ago
9

1) Greaters sold 30 milkshakes last week. 20%. of the milkshakes had whipped cream on them. How many shakes had whipped cream? A

nswer: I​
Mathematics
1 answer:
Semenov [28]3 years ago
8 0

Answer:

6

plz vote me brainliest

Step-by-step explanation:

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A paraboloid container is being filled with fluid at the rate of 4.5 cubic feet per minute. At what rate is the level of fluid c
docker41 [41]

Answer:

2.62 ft./min

Step-by-step explanation:

Just took the test.

7 0
3 years ago
The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.895 g and a standard deviation
kvasek [131]

Answer:

3.67% probability of randomly seleting 37 cigarettes with a mean of 0.809 g or less.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 0.895, \sigma = 0.292, n = 37, s = \frac{0.292}{\sqrt{37}} = 0.048

Find the probability of randomly seleting 37 cigarettes with a mean of 0.809 g or less.

This is the pvalue of Z when X = 0.809.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.809 - 0.895}{0.048}

Z = -1.79

Z = -1.79 has a pvalue of 0.0367

3.67% probability of randomly seleting 37 cigarettes with a mean of 0.809 g or less.

5 0
3 years ago
The measurement, y, varies directly with regard to another value, x. If y = 9 and x = 24, find x for y = 25. 9.4 50 66.7
ale4655 [162]

Answer:

<u>The correct answer is C. 66.7</u>

Step-by-step explanation:

1. y varies directly with regard to x

y = 9 and x = 24

If y = 25, what is the value of x?

2. For finding that value of x, first of all, we should understand what happened to y.

If y moves from 9 to 25 it means that y has been multiplied by 2.77, using this simple division

25/9 = 2.777

3. And we should use that same number or value to calculate the new value of x

If x was 24, now the new value of x is 24 * 2.777

24 * 2.777 = 66. 67 or 66.7 (rounding to just one decimal)

<u>The correct answer is C. 66.7</u>

4 0
3 years ago
Austin's truck has a mass of 2000 kg when traveling at 22.0 m/s, it brakes to a stop in 4.0 s. show that the magnitude of the br
olga2289 [7]
Since F=m•a, you want to show that a = -5.5

5 0
3 years ago
Read 2 more answers
A church rings its bells every 15 minutes, the school rings its bells every 20 minutes and the day care center rings its bells e
ankoles [38]

Answer:

As few as just over 345 minutes (23×15) or as many as just under 375 minutes (25×15).

Imagine a simpler problem: the bell has rung just two times since Ms. Johnson went into her office. How long has Ms. Johnson been in her office? It could be almost as short as just 15 minutes (1×15), if Ms. Johnson went into her office just before the bell rang the first time, and the bell has just rung again for the second time.

Or it could be almost as long as 45 minutes (3×15), if Ms. Johnson went into her office just after the bells rang, and then 15 minutes later the bells rang for the first time, and then 15 minutes after that the bells rang for the second time, and now it’s been 15 minutes after that.

So if the bells have run two times since Ms. Johnson went into her office, she could have been there between 15 minutes and 45 minutes. The same logic applies to the case where the bells have rung 24 times—it could have been any duration between 345 and 375 minutes since the moment we started paying attention to the bells!

Step-by-step explanation:

7 0
3 years ago
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