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Alenkinab [10]
4 years ago
10

George wants to invest $20,000 One investment pays interest at a rate of 18 2/3% while another pays interest at a rate of 0.1872

which is the better investment?
Mathematics
1 answer:
xz_007 [3.2K]4 years ago
7 0

Answer:

Investment with interest rate 0.1872 is better

Step-by-step explanation:

Given as :

George investment principal = $20,000

The Rate of interest  (R1)   = 18 \frac{2}{3} % = \frac{56}{3} %

I.e   R1 = 18.67 %

Again The The Rate of interest  (R2)  = 0.1872  = 18.72 %

Let the time period for both rate of interest = 1 years

Now from compound interest method

Amount = Principal × (1 + \frac{Rate}{100})^{Time}

Or,    A 1 = $ 20 , 000 × (1 + \frac{18.67}{100})^{1}

Or,    A 1 = $ 20 ,000 × 1.1867

∴       A 1 = $ 23,734

And   A 2 = $ 20 , 000 × (1 + \frac{18.72}{100})^{1}

Or,     A 2 = $ 20 ,000 × 1.1872

∴        A 2 = $ 23,744

Hence From the calculation of both amount it is clear that , investment with interest rate 0.1872 is better . Answer

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77julia77 [94]

Answer:

Step-by-step explanation:

General form of the linear differential equation can be written as:

\frac{dy}{dx}+P(x)y=Q(x)

For this case, we can rewrite the equation as:

\frac{dy}{dx}+\frac{1}{2x}y=\frac{\sqrt{x}}{x}

Here P(x) =\frac{1}{2x}; Q(x)=\frac{\sqrt{x}}{x}

To find the solution (y(x)), we can use the integration factor method:

Fy(x)=\int Q(x)Fdx+C \rightarrow F=e^{\int P(x)dx

Then F=e^{\int \frac{1}{2x}dx}=e^{\frac{1}{2}\ln|x|\right}=\sqrt{|x|}

So, we can find:

y\sqrt{|x|}=\int \frac{\sqrt{x}\sqrt{|x|}}{x}dx+C

Suppose that x\in \double R, then \sqrt{|x|}=\sqrt{x} , and we find:

y\sqrt{x}=x+C \rightarrow y(x)=\sqrt{x}+\frac{C\sqrt{x}}{x}

To check our solution is right or not, put your y(x) back to the ODE:

y' = \frac{1}{2\sqrt{x}}-\frac{C}{2\sqrt{x^{3}}}

2xy'=\frac{x-C}{\sqrt{x}}

2xy'+y=\frac{x-C}{\sqrt{x}}+\sqrt{x}+\frac{C\sqrt{x}}{x}=2\sqrt{x}

(it means your solution is right)

3 0
2 years ago
Jon hikes 13.5 mi at a constant rate of 3 mi/h. How many hours does he hike? 4.0 h 4.5 h 10.0 h 10.5 h
dezoksy [38]

Answer: 4.5

Step-by-step explanation: because, 3x4=12 then you have 1.5 left and 1.5 is half of three so you would have .5 and you then add 4+.5 to get 4.5

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4 years ago
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Which of the algebraic expressions are not linear expressions? Select all that apply. a. 3x - 2 b. -9y c. -7x^2^ + 4x d. -1/2x^2
Sedaia [141]

Answer:

c, d and e

Step-by-step explanation:

A linear expression is an expression in which sum of exponents of variables is at most 1 in each of its terms.

Option a: 3x - 2

Here, the exponent of the variable is 1.

So, it is a linear expression.

Option b: -9y

Here, the exponent of the variable is 1.

So, it is a linear expression.

Option c: -7x^2 + 4x

Here, the highest exponent of the variable is 2.

So, it is NOT a linear expression.

Option d: -\frac{1}{2} x^2

Here, the exponent of the variable is 2.

So, it is NOT a linear expression.

Option e: 8xy

Here, sum of exponents of variables is 2.

So, it is NOT a linear expression.

Hence, c, d and e are NOT algebraic expressions.

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Step-by-step explanation:

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6 0
3 years ago
How can (4x⁵/2x²)³ be solved in 2 different ways
Margaret [11]

We assume that we need to simplify the expression in two different ways.

Answer:

One way: Raise both, the numerator and denominator, to the third power, and then simplify the expression.

Second way: Simplify the terms inside parentheses, and then raise the result to the third power.

The result of both ways is the same: \\8x^{9}

Step-by-step explanation:

<em>One way</em>

Raise both, the numerator and denominator, to the third power, and then simplify the expression:

\\ (\frac{4x^{5}}{2x^{2}})^{3}

\\ (\frac{64x^{5*3}}{8x^{2*3}})

\\ (\frac{64x^{15}}{8x^{6}})

\\ \frac{64}{8}\frac{x^{15}}{x^{6}}

\\8x^{9}

This is the first simplification.

<em>Second way</em>

Simplify the terms inside parentheses, and then raise the result to the third power.

\\ (\frac{4x^{5}}{2x^{2}})^{3}

\\ (\frac{4}{2}*\frac{x^{5}}{x^{2}})^{3}

\\ (2*x^{5-2})^{3}

\\ (2*x^{3})^{3}

\\ (2^{3}*x^{3*3})

\\ (8*x^{9})

or \\ 8x^{9}.

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3 years ago
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