Please give more information
Answer:
x=0,![\sqrt[6]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B5%7D)
Decimal form,
x=0,1.30766048......
Step-by-step explanation:
x
=
x
-
=0
(take x as a common factor)
x(
-
)=0
So,
x=0 and
-
=0
for
-
=0
(add
for both sides)
=
x=
(multiply 3 by 2)
x=![\sqrt[6]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B5%7D)
So,
x=0,![\sqrt[6]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B5%7D)
Sorry for the hand writing. But you want to factor out a 4y^2 which will result in (9y^2-1). Then you will factor out the equation in parentheses to (3y-1)(3y+1). Don’t forget to put the 4y^2 out front!
Answer:
a=1 or a=5/6
Step-by-step explanation:
I'm going to attempt to factor 6a^2-a-5
a=6
b=-1
c=-5
Find two numbers that multiply to be a*c and add to be b.
a*c=-30 =-6(5)
b=-1 =-6+5
So replace -a with -6a+5a in the expression we started with
6a^2-6a+5a-5
now we factor by grouping
6a(a-1)+5(a-1)
(a-1)(6a-5)
Now let's solve the equation:
(a-1)(6a-5)=0
So a=1 or a=5/6