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KATRIN_1 [288]
3 years ago
11

Please help on this thank you 10 points!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
dimaraw [331]3 years ago
3 0

i think it would be two

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BRAINLIEST..........show expressions too<333
vovikov84 [41]

Answer:

9.) t=.05m+20

10.) t=.10m+5

11.) 300 minutes of calling would make the two plans equal.

12.) Company B.

Step-by-step explanation:

Let <em>t</em> equal the total cost, and <em>m,</em> minutes.

Set up your models for questions 9 & 10 like this:

<em>total cost = (cost per minute)# of minutes + monthly fee</em>

Substitute your values for #9:

t=.05m+20

Substitute your values for #10:

t=.10m+5

__

To find how many minutes of calling would result in an equal total cost, we have to set the two models we just got equal to each other.

.10m+5=.05m+20

Let's subtract 5 from both sides of the equation:

.10m=.05m-15

Subtract .05m from both sides of the equation:

.05m=15

Divide by the coefficient of m, in this case: .05

m=300

__

Let's substitute 200 minutes into both of our original models from questions 9 & 10 to see which one the person should choose (the cheaper one).

Company A:

t=.05(200)+20

Multiply.

t=10+20

Add.

t=30

Company B:

t=.10(200)+5

Multiply.

t=20+5

Add.

t=25

<em />

6 0
3 years ago
A study was conducted on the relationship between speeds of cars and gas mileage. The correlation coefficient was 0.45. Later, t
True [87]

Answer:

0.45

Step-by-step explanation:

The correlation coefficient is used to measure the relationship between how two variables change. In this question, the two variables are cars speed and gas mileage. Since the speedometers were wrong as they were 5 mph too high in a constant manner, then the correlation between how changes in speed affect gas mileage will not be changed.

For example, if we are measuring how an increase of 15 mph decreased gas mileage, we are looking at the change in speed and it is the same if we start with 75 mph and then increase speed to 90 mph, or if we start with 45 mph and then increase to 60 mph. The change in speed for both cases will remain unchanged at 10 mph.

Now, since we have seen that the change in speed remains unchanged and since correlation coefficient is a measure of the relationship between how two variables change, then the new value of the correlation coefficient will remain the same as 0.45.

8 0
3 years ago
Please help! I'll also give you a brainlist.
nekit [7.7K]
Range: (-infinity, 4]
the ] signifies that the four is included in the range, rather than ) which means reaching but never approaching. this is why we use ( ) for - and + infinity, cause it can never be reached.

minimum: (-infinity, infinity)
keep it in same format as you have for the maximum

increasing
the interval -infinity
6 0
3 years ago
Help help help help help help help please ​
ArbitrLikvidat [17]

Answer:

-3 I think

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please answer this question I need this urgent Help meeeee
iren [92.7K]

Answer:

\frac{s}{2t}

Step-by-step explanation:

When you have exponents above a like term and they are being multiplied together, you add them.

For example:

a^{x} *a^{y} = a^{x + y}

So let's group like terms in the numerator:

4r^{3} r^{-5} s^{-2} s^{-1}t   We can add terms like in the example.

4 r^{-2} s^{-3} t

Let's rearrange the denominator.

8r^{-2} s^{-4} t^{2}

Now we have:

\frac{4r^{-2} s^{-3}t}{8 r^{-2} s^{-4} t^{2} }  Cancel like terms

4/8 = 1/2    

r^{-2} /r^{-2} = 1  So it cancels

s^{-3} / s^{-4} = s^{-1} = s Since s is raised to the -1 it goes on top and becomes s.

t / t^{2}  = 1/t

Now we combine everything back together:

\frac{s}{2t}

8 0
3 years ago
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