The equation of the line which passes through the point (-1, 2) and is parallel to the line y = x + 4 is y = x + 3
<h3><u>Solution:</u></h3>
Gtiven that line passes through the point (-1, 2) and parallel to line y = x + 4
We have to find the equation of line
<em><u>The equation of line in slope intercept form is given as:</u></em>
y = mx + c ---------- eqn 1
where "m" is the slope of line and "c" is the y - intercept
<em><u>Let us first find the slope of line</u></em>
Given equation of line is y = x + 4
On comparing the given equation of line y = x + 4 with general slope intercept form y = mx + c,
we get slope of line "m" = 1
We know that slopes of parallel lines are equal
So the slope of line parallel to line having equation y = x + 4 is also 1
Now we have to find the equation of line having slope "m" = 1 and passes through point (-1, 2)
Substitute m = 1 and (x, y) = (-1, 2) in eqn 1
2 = 1(-1) + c
2 = -1 + c
c = 3
<em><u>Thus the required equation of line is:</u></em>
Substitute c = 3 and m = 1 in eqn 1
y = 1x + 3
y = x + 3
Thus the required equation of line is found out
