A deep-sea exploring ship is pulling up a diver at the rate of 25 feet per

ANSWER QUICK!! 75 PTS!!!

iogann1982 [59]

Answer:

2) x = -2 , y = 2

3) no solution exists

Step-by-step explanation:

Solve the following system:

{-2 x - 3 y = -2

y = 2 x + 6

Hint: | Perform a substitution.

Substitute y = 2 x + 6 into the first equation:

{-2 x - 3 (2 x + 6) = -2

y = 2 x + 6

Hint: | Expand the left hand side of the equation -2 x - 3 (2 x + 6) = -2.

-2 x - 3 (2 x + 6) = (-6 x - 18) - 2 x = -8 x - 18:

{-8 x - 18 = -2

y = 2 x + 6

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for x:

{-8 x - 18 = -2

y = 2 x + 6

Hint: | Isolate terms with x to the left hand side.

Add 18 to both sides:

{-8 x = 16

y = 2 x + 6

Hint: | Solve for x.

Divide both sides by -8:

{x = -2

y = 2 x + 6

Hint: | Perform a back substitution.

Substitute x = -2 into the second equation:

Answer: {x = -2 , y = 2

4 0

3 years ago

Three forces act on a hook. Determine the magnitude of the resultant of the force.

Novay_Z [31]

Use Hooke's law... (just kidding)

Break down each force vector into horizontal and vertical components.

$\vec F_1=(1000\,\mathrm N)(\cos30^\circ\,\vec x+\sin30^\circ\,\vec y)\approx(866.025\,\mathrm N)\,\vec x+(500\,\mathrm N)\,\vec y$

$\vec F_2=(1500\,\mathrm N)(\cos160^\circ\,\vec x+\sin160^\circ\,\vec y)\approx(-1409.54\,\mathrm N)\,\vec x+(513.03\,\mathrm N)\,\vec y$

$\vec F_3=(750\,\mathrm N)(\cos195^\circ\,\vec x+\sin195^\circ\,\vec y)\approx(-724.444\,\mathrm N)\,\vec x+(-194.114\,\mathrm N)\,\vec y$

The resultant force is the sum of these vectors,

$\vec F=\displaystyle\sum_{i=1}^3\vec F_i\approx(-1267.96\,\mathrm N)\,\vec x+(818.916\,\mathrm N)\,\vec y$

and has magnitude

$|\vec F|\approx\sqrt{(-1267.96\,\mathrm N)^2+(818.916\,\mathrm N)^2}\approx1509.42\,\mathrm N$

The closest answer is D.

5 0

2 years ago

Jamie has 6 coins. Each coin is either a penny or a nickel. How much money does Jamie have?

seraphim [82]

He would have 6-30 cents

3 0

2 years ago

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The double number line shows that 3 back-to-school packages contain 36 pencils.

lord [1]

Answer:

The answer is A

Step-by-step explanation:

i just got it right

7 0

3 years ago

Kite WXYZ is graphed on a coordinate plane. What is the approximate perimeter of the kite? Round to the nearest tenth. 10.6 unit

Archy [21]

Answer-

Perimeter of the kite is 16.2 units

Solution-

As WXYZ is a kite, so two disjoint pairs of consecutive sides are congruent, i.e WX=XY and WZ=ZY

So, perimeter of the kite WXYZ is,

$=2(\overline{WX}+\overline{WZ})$

And

$\overline{WX}=\sqrt{(1-3)^2+(1-4)^2}=\sqrt{(-2)^2+(-3)^2}=\sqrt{4+9}=\sqrt{13}$

$\overline{WZ}=\sqrt{(1-3)^2+(1+3)^2}=\sqrt{(-2)^2+(4)^2}=\sqrt{4+16}=\sqrt{20}$

So, perimeter will be,

$P=2(\sqrt{13}+\sqrt{20})=16.15\approx 16.2\ units$

4 0

2 years ago

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