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valina [46]
3 years ago
9

Savanna is playing a game with her friends. She tells them to each pick a number, and then she directs them to: 1. Multiply thei

r number by 4 2. Subtract 6 from that number 3. Divide that number by 2. Once they do that, they each tell Savanna their number a. Arturo says his "new" number is -15. What number did Arturo start with?
Mathematics
1 answer:
Kaylis [27]3 years ago
7 0

Answer:

x  = - 6

Step-by-step explanation:

Let  x  b number, according to instructions´ we must

1.-Multiply  by  4

2.-Subtract  6

3.-Divide by 2

4.-Arturo says his new number  - 15

4,.Which one was the original number   ??

The maths expression for that  is :

(4*x - 6 ) / 2  =  -  15

we solve for x

4x  -  6  = - 30

4x   =  - 24

x  = - 6

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I need help with this ASAP please!!
Ilia_Sergeevich [38]

Answer:

Translation 1 unit left

Step-by-step explanation:

we have

f(x)=x

g(x)=(x+1)

we know that

The rule of the transformation of f(x) to g(x) is equal to

f(x) ------> g(x)

(x,y) -----> (x-1,y)

That means----> The translation is 1 unit to the left

6 0
3 years ago
Find the missing term in the pattern.
Whitepunk [10]

Answer:

20

Step-by-step explanation:

6 + 2 = 8

8 + 3 = 11

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3 years ago
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Vector V is shown in the graph below.
Lady_Fox [76]

Answer:

v = -8i - 6j

Step-by-step explanation:

The starting point is (9, 9)

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The j is the vertical component.

Therefore, to go from the start to the end of the line, we need to travel negative 8 units (horizontally) and negative 6 units (vertically).

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3 years ago
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3 years ago
Express 2x+1/(x-2)(x²+1) as a partial fraction.
Oduvanchick [21]

Answer:

Partial fraction = 1/(x-2) - x/(x^2+1)

Step-by-step explanation:

Question:

Express 2x+1/(x-2)(x²+1) as a partial fraction.

Note: it will be assumed that there was a typo in the interpretation of parentheses to mean

(2x+1) / ( (x-2)(x^2+1) )

Let

(2x+1) / ( (x-2)(x^2+1) ) = A/(x-2) + (Bx+C)/(x^2+1) .........................(0)

(2x+1) / ( (x-2)(x^2+1) ) = (A(x^2+1)+(Bx+C)(x-2)) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = (Ax^2+A+Bx^2+(C-2B)x-2C) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = ( (A+B)x^2+(C-2B)x+A-2C ) / ( (x-2)(B/(x^2+1) )

Match numerators

2x+1 = (A+B)x^2+(C-2B)x+A-2C

Match coefficients,

A+B = 0 ..................(1)

-2B+C = 2 .................(2)

A-2C = 1 ...................(3)

Solve for A, B and C

Substitute A from (1) in (3)

-B - 2C =1  

transpose and solve for B

B = -2C-1  ....................(4)

Substitue B from (4) in (2)

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simplify

5C = 2-2 = 0

C=0  ..........................(5)

substitute (5)  in (4)

B = -2C-1 = -1  ...............(6)

Substitue (6) in (1)

A+(-1) = 0

A=1 .............................(7)

Using values from (7), (6) and (5) to substitute in (0)

we get

(2x+1) / ( (x-2)(x^2+1) ) = 1/(x-2) - x/(x^2+1)

as the required partial fraction

7 0
4 years ago
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