A line segment from a vertex to the midpoint of the opposite side is a "median". A median divides the area of the triangle in half, as it divides the base in half without changing the altitude.
AAMC is half AABC. AADC is half AAMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
ABMC is half AABC. ABMD is half ABMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
Then, AADC = 1/4 AABC = ABMC, so AADC = ABMC by the transitive property of equality.
Answer:
x = 5.14
Step-by-step explanation:
Both angles are equal so
5x-6 = 11x-42
42-6 = 11x - 5x
36 = 7x
x = 5.14
You probably are interested in expressing the given equation as a quadratic equation in u, as it will make it easy to find the solutions.
Let u = x²
So,
u² = x⁴
So, the given equation can be written as:
u² - 17u + 16 = 0
Now the equation is quadratic in u and the solutions can be calculated using quadratic formula or factorization.
Answer:
2
Step-by-step explanation:
