Answer:
We have the next relation:
A = (b*d)/c
because we have direct variation with b and d, but inversely variation with c.
Now, if we have 3d instead of d, we have:
A' = (b*(3d))/c
now, we want A' = A. If b,c, and d are the same in both equations, we have that:
3bd/c = b*d/c
this will only be true if b or/and d are equal to 0.
If d remains unchanged, and we can play with the other two variables we have:
3b'd/c' = bd/c
3b'/c' = b/c
from this we can took that: if c' = c, then b' = b/3, and if b = b', then c' = 3c.
Of course, there are other infinitely large possible combinations that are also a solution for this problem where neither b' = b or c' = c
<span>The equation would be 5x + 0.10y = 35, and since y equals 100, the 0.10y = 10. Then you get your equation which would be 5x + 10 = 35. and you can use subtraction property of equality and subtract 10 from both sides which gives you 25. So x would equal 5. In this case x represents number of dogs walked. Hope this helps! :D</span>
Answer:
is B
Step-by-step explanation:
because the cost at store B is $2.00 greater that at store A
