The LCD = 6x^2y^3 ( because LCD of 3 and 6 = 6, LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)
now divide 3x^2y into the LCD then multiply this by 5 to get the first term in the numerator and do similar process to get second term, so we get:-
5(2y^2) - 4(x)
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6x^2y^3
= 2( 5y^2 - 2x)
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6x^2y^3
= 5y^2 - 2x
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3x^2y^3
20 boxes because 6 times 5 equals 30 so 4 times 5 is 20
Answer:
9
Step-by-step explanation:
three more than the sum of (3,3)
lets first do the sum of (3,3)
3 + 3 = 6
now it's asking<em> three more than the sum of (3,3)</em>
three more than means we need to add 3 to 6
6 + 3 = 9
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Answer:
a. 1
b. any number to the zero power is just the product of no numbers at all, which is the multiplicative identity, 1
Step-by-step explanation:
