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Anika [276]
3 years ago
7

Darius has mowed 1/5 of his backyard. Which is a better estimate for how much of the lawn he has left to mow: almost all of the

lawn or about half of the lawn?
Mathematics
2 answers:
makkiz [27]3 years ago
7 0
The correct response would be almost all

astraxan [27]3 years ago
4 0
1/5 means like very little, so almost all of it

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A fence is being built around a rectangular garden. The length of the garden is 35 feet, and the total fencing used to enclose t
liraira [26]
The garden's width is 45. We know this because
35 \times 2
(length)
35 \times 2 + 2x = 160 \\
35x2 is 70 and you need to neutralize that by taking away 70 from both sides.
160 - 70 = 90
2x = 90
Now divide by 2 on both sides to neutralize the 2 times x.
90 \div 2 = 45
meaning that leaves us with
x = 45
3 0
3 years ago
Read 2 more answers
Given the following sets:
hjlf
<h3>Answer:  10</h3>

===========================================================

Explanation:

Even though your teacher doesn't want you to list the items of the set, it helps to do so.

We'll be working with these two sets

A = {b, d, f, h, j, I, n, p, r, t}

C =  {d, h, I, p, t}

When we union them together, we combine the two sets together. Think of it like throwing all the letters in one bin rather than two bins.

A u C = {b, d, f, h, j, I, n, p, r, t,   d, h, I, p, t  }

The stuff that isn't bolded is set A, while the stuff that is bolded is set C

After we toss out the duplicates, we end up with this

A u C = {b, d, f, h, j, I, n, p, r, t}

But wait, that's just set A. Notice how everything in set C can be found in set A. This indicates set C is a subset of set A.

That's why all of the stuff in bold was tossed out (because they were duplicates of stuff already mentioned).

Once we determine what set A u C looks like, we count out the number of items in that set to determine the final answer.

There are 10 items in {b, d, f, h, j, I, n, p, r, t} which means 10 is the final answer.

----------------------------

An alternative method is to use the formula below

n(A u C) = n(A) + n(C) - n(A and C)

n(A u C) = 10 + 5 - 5

n(A u C) = 10

The notation n(A and C) counts how many items are found in both sets A and C at the same time. But as mentioned earlier, this is identical to just counting how many items are in set C. So we'll have n(C) cancel out with itself.

In short, n(A u C) = n(A) = 10

8 0
3 years ago
Metric mania <br> How many shoes would it take to make 1 kilometer
Lady_Fox [76]

Answer:

Well since my shoe is 8.5 inches, you will take 4 whole shoes to make a meter. Therefore, you will have to take 4,000 shoes to make a kilometer because 1 kilometer=1000. (:

Step-by-step explanation:

4 0
3 years ago
A new fitness center opens with 120 members. Every month the fitness center increases the number of members by 40 members. How m
soldier1979 [14.2K]

Answer:

<u>240 members</u>

Step-by-step explanation:

Let y = total and x = no. of months

y = 40x + 120

= 40(3) + 120

= 120 + 120

= <u>240 members</u>

4 0
2 years ago
Compare the investment below to an investment of the same principal at the same rate compounded annually.
Andrews [41]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus twice} \end{array}\dotfill &2\\ t=years\dotfill &19 \end{cases} \\\\\\ A=5000\left(1+\frac{0.08}{2}\right)^{2\cdot 19}\implies A\approx 22194.067 \\\\[-0.35em] ~\dotfill

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &19 \end{cases} \\\\\\ A=5000\left(1+\frac{0.08}{1}\right)^{1\cdot 19}\implies A\approx 21578.505

6 0
2 years ago
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