1. 25% which is bb
2. All living things are made of cells
3. Grams, mass
Hope that helps.
Answer:
This could be possible if the wife is a carrier of the FMO3 allele. Therefore the two carrier parents must have passed the defective alleles to the child, who now possessed the gene for the FMO3, and said to be dominant for the fish odor.
In genetics a Carrier is an individual who inherited a defective allele (FMO3) , but do not show the manifestations of the allele, or symptoms of the diseases attributed to it. Therefore the wife is a Carrier for the allele if the child could show this symptoms of fish odor.
Explanation:
Answer: The genotype ratio of offsprings of a cross between one homozygous tall plant and one heterozygous tall plant is 2TT:2Tt
The phenotype ratio is that all offsprings will be tall.
The genotype ratio of a cross between two heterozygous red flowers is 1RR:2Rr:2rr. The phenotype ratio is 3 Red flowers: 1 white flower.
Explanation: From the information given, tall is dominant and short is recessive while red is dominant and white is recessive.
Let T represent the allele for tall height, t represent the allele for short height, R represent allele for red flowers and r represent allele for white flowers.
The genotype of a homozygous tall plant is TT, the genotype of a heterozygous tall plant is Tt, the genotype of a heterozygous red flowered plant is Rr.
The possible genotypes of offsprings of a cross between one homozygous tall plant and one heterozygous tall plant are TT and Tt.
Tt will manifest outwardly as tall because T is dominant over t. Therefore, all the offsprings will be tall.
The possible genotypes of a cross between two heterozygous red flowers are RR, Rr and rr. RR will manifest as red, Rr will also manifest as red because R is dominant to r while rr will manifest as white because white allele (r) is recessive. Therefore 3 plants will be red-flowered while 1 plant will be white flowered.
See the attached punnet squares for details of the cross.