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3 years ago

Gradient if u good hhhhhhhhh

Mathematics

2 answers:

slava [35]3 years ago

7 0

Answer:

Step-by-step explanation:

Put your finger where the blue line starts (at 0,1) and another where it next intersects 2 whole numbers.

Bring your first finger across and your second down until they meet. You count how many squares each finger took to meet. So that's 1 on the X, 2 on the Y. 2 ÷ 1= 2.

So your answer is two.

Hope this helps. :)

Fed [463]3 years ago

5 0

Answer:

m (gradient) = 2

Step-by-step explanation:

gradient formula:

y2- y1/ x2 - x1

lowest point = (x1, y1)=(1,0)

highest point = (x2, y2)=(6,10)

10 - 0/ 6 - 1

=10/5

simplify:

= 2/1

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How do I simply -3/5(-8+5/9x-3)

prohojiy [21]

33/5 - x/3

hope this helps!

7 0

3 years ago

Read 2 more answers

Washington (CNN) About three-quarters of Americans (77%) approve of President Donald Trump's decision to meet with North Korean

snow_tiger [21]

Answer:

b. The margin of error would decrease.

Step-by-step explanation:

Margin of error of a confidence interval:

The margin of error of a confidence interval has the following format:

$M = z\frac{\sigma}{\sqrt{n}}$

In which z is related to the confidence level, $\sigma$ is the standard deviation of the population and n is the size of the sample.

This means that the margin of error is inversely proportional to the size of the sample, which means that if the sample size increases, the margin of error decreases.

In this question, the sample size is increased, leading to a smaller margin of error. So the correct answer is given by option b.

8 0

2 years ago

Determine whether a quadratic model exists for the set of values below. If so, write the model. f(0) = -4, f(3) = -19, f(-1) =

Vikentia [17]

Answer:

A) The model exists: f(x) = -3x^2 +4x -4

Step-by-step explanation:

A quadratic model will always exist for 3 given points, provided they are not on a line. In that case, a linear model is appropriate.

Here, the slope between -1 and 0 is positive, and the slope between 0 and 3 is negative. Thus, we know these points are not collinear, and a model must exist.

The model is most easily found using a quadratic regression tool. Such is shown in the attachment. It tells us that ...

f(x) = -3x^2 +4x -4