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nalin [4]
3 years ago
9

Evaluate the expression for w = 4, x = 9, and y = 11. Simplify your answer. w − x + y /x − y =

Mathematics
2 answers:
shepuryov [24]3 years ago
4 0

4 - 9 + 11 / 9 - 11

To solve this, I suggest using PEMDAS and starting with division. 11/9 = 1.3 (rounded).

4 - 9 + 1.3 - 11

Now proceed from left to right to get the final answer of:

-14.7

Hope this helps!

dmitriy555 [2]3 years ago
3 0

Basically, you want to plug in these values into the equation.

(4)-(9)+(11/9)-11

Simplify it

-5+11/9- 11

-16+11/9

=16 11/9


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I think y=2 there both on the 2 y intercept straight from each Other
6 0
3 years ago
Given Trapezoid JOKE with m
yKpoI14uk [10]

Answer:

m∠J =90°
m∠O = 140°

Step-by-step explanation:

We see here angle J having 90°, pure right angle shape.

m<J=90

Then we find the total interior angle using (n-2)*180

(4-2)*180

360°

So, m∠O = 360° - m∠J - m∠E -m∠K

m∠O = 360° - 90° - 80° -50°

m∠O = 140°

3 0
2 years ago
Read 2 more answers
the area of a rectangular volleyball court is 1800 square feet the courts length is twice it width write a system of equations t
Marianna [84]

Answer:

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

Step-by-step explanation:

Let

x ----> the length of rectangular volleyball court

y ---> the width of the rectangular volleyball court

we know that

The area of the rectangular volleyball court is equal to

A=xy

A=1,800\ ft^2

so

1,800=xy ----> equation A

x=2y -----> equation B

substitute equation B in equation A

1,800=(2y)y

1,800=2y^2

Solve for y

Simplify

900=y^2

take square root both sides

y=30\ ft

<em>Find the value of x</em>

x=2y

substitute the value of y

x=2(30)=60\ ft

therefore

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

7 0
3 years ago
49/10 as a mixed number
Anni [7]
 ⇒ \frac{49}{10} 

\frac{49}{10} is a improper fraction. 
\frac{49}{10} as a mixed number would be 4 \frac{9}{10}

⇒10 x 4 = 40 
⇒40 + 9 = 49 

\frac{49}{10} = 4 \frac{9}{10} 

⇒ANSWER = 4 \frac{9}{10}

 
7 0
3 years ago
Read 2 more answers
The distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on y
kaheart [24]

Answer:

d(1) = -3 and d(2)= -28

Step-by-step explanation:

Given that the distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on your distance x, in meters, from the stabilized point

d(x)=-4x^3+x^2

For finding out the distances for x=1 and x=2

let us substitute 1 and 2 for x

d(1) = -4(1^3)+1^2 = -3

d(2) = -4(2^3)+2^2 \\= -28

d(1) = -3 and d(2)= -28

3 0
3 years ago
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