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DENIUS [597]
3 years ago
13

Complete the recursive formula of the arithmetic sequence 14, 30, 46, 62, ....

Mathematics
1 answer:
Sauron [17]3 years ago
5 0

Answer:

They are adding 16 to the number each time. So the next number in the sequence would be 78.

Step-by-step explanation:

d(1) = 14

d(n) = d (n-1) + 16

14 + 16 = 30

30 + 16 = 46

46 + 16 = 62

62 + 16 = 78 and so on...

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Please please please help me with this answer
Rasek [7]

x = number of packages he bought

y = number of popsicles in each package

Here are the two equations:

xy = 54

x = 3 + y

Using the substitution method, you can solve them to find x and y.

(3 + y)y = 54,

3y + y^2 = 54

y^2 + 3y - 54 = 0

Solve the quadriatic equation:

(y +9)(y - 6) = 0

y = -9, 6.

Plug y into: xy = 54

x(-9) = 54, x = -6.

x(6) = 54, x = 9.

So he bought 9 packages of popsicles, bc you can't bye -6 packages.

3 0
3 years ago
Are the fractions equivalent?
dangina [55]

Answer:

7. no

8.yes

9.yes

10.no

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4 0
3 years ago
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How to solve exponential equations
Anettt [7]
Is there a specific question?

Pemdas is usually the general order to solving exponential equations.

(P) Parenthesis, as in simplify what is inside a parenthesis first.
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(D) Division
(A) Addition
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7 0
3 years ago
Read 2 more answers
Determine the equation of each line with the following properties:
iris [78.8K]

Answer:

a) y =2/3 x + 7.

b) x = -1

c) y = -4/5 x - 1/5

d) y = -3/2 x + 5/2.

Step-by-step explanation:

a) Intercept form y = mx + b where m = 2/3 and  b = 7

b) y can take any value but x is always -1.

c) Slope m = (-1-3)/ (1 - -4)

= -4/5

Using point-slope form where m = -4/5 and x1 y1 = 1 , -1:

y - y1 = m(x - x1)

y - -1 = -4/5(x - 1)

y + 1 = -4/5x + 4/5

y = -4/5 x - 1/5

d)  The slope m of the line perpendicular to this line is:

-1 / 2/3

m = -3/2.

When x = -1 , y = 4 so using the slope intercept form of a line

y = mx + b

4 = -3/2 * -1 + b  where b = the y-intercept.

4 = 3/2 + b

b = 4 - 3/2 = 5/2.

The equation is  y = -3/2 x + 5/2.

3 0
3 years ago
Help PLSS HELP ASAP<br> TAN^2 X + SQRT3 TAN X =[0}
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\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}

see this attachment ☝☝☝

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