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sergiy2304 [10]
3 years ago
7

What is the range of y = –3sin(x) – 4?

Mathematics
2 answers:
klemol [59]3 years ago
7 0

Answer:  [-7,-1]

Explanation:

range of a function is  that limit in which variation of any function is possible.

general range of sinx is between [-1,1]

-1\leqsinx\leq1                             (A)

our required function is y= -3sinx - 4

So, as to obtain this function we will multiply  the each side in Equation (A) by -3 we will get

-3\geq-3sinx\geq3                            (B)

now subtract from  4 from each side of (B) we will get

-7\geq-3sinx-4\geq-1

Hence, required range of the given function y= -3sinx-4 is [-7,-1].


Ilia_Sergeevich [38]3 years ago
4 0
<span>What is the range of y = –3sin(x) – 4?

[-7,-1]
{y | -7 </span>≤ y ≤ -1}
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