This is what I got hope it helps!
http://www.mathopenref.com/coordintro.html
http://www.cpalms.org/Public/PreviewResourceAssessment/Preview/70464
Answer:
Attached diagram A'B'C'D'
Step-by-step explanation:
Given is a quadrilateral ABCD. It says to draw a dilated version with a scale factor 2/3.
We see that scale factor is less than 1 which means it shrinks the image to a smaller one.
To draw a scaled copy, we need to find the lengths of its sides.
To do so, we can draw the diagonals AC & BD, and they intersect at origin O(0,0) such that OA= -2, OB= 2, OC= 4, OD= -4.
Applying a scale factor of 2/3, we get OA' = -4/3, OB' = 4/3, OC' = 8/3, OD' = -8/3.
So we have attached a scaled copy A'B'C'D' of quadrilateral ABCD with a scale factor 2/3.
Answer:
<h2>1. subtract 3x, subtract 4, divide by -4</h2><h2 /><h2>2. add x</h2>
Step-by-step explanation:
1 + 3x = -x + 4.
subtract 3x
1 = -4x + 4
subtract 4
-3 = -4x
divide by -4
(-3)/(-4) = (4x)/(-4) ⇌ x = 3/4
-x + 6 = 5 - 3x
subtract 5
-x + 1 = - 3x
add x
1 = -2x