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tankabanditka [31]
4 years ago
8

An astronaut visited Mars. His weight on Earth was 180 pounds, and his weight on Mars was only 72 pounds. He removed a rock with

a weight of 16 pounds on Mars. What is the weight of the rock on Earth?
Mathematics
1 answer:
Damm [24]4 years ago
5 0
Find the percentage of ratio to weight.

180/72 = 2.5

So 2.5 Earth Pounds = 1 Mars Pound

16*2.5 = 40 Pounds the rock weighs on earth.
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Answer:

C(g) = 10 + 15g

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The monthly charges of Company C for using 2 Gigabyte of data usage.

Step-by-step explanation:

The cell phone plan from Company C costs $10 per month, plus $15 per gigabyte for data used. The plan from Company D costs $80 per month, with unlimited data.

Now, the monthly cost in Company C for using g gigabyte of data will be  

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Again, the monthly cost in Company D for using g gigabyte of data will be  

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3 years ago
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0.18
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6 0
3 years ago
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Dvinal [7]

Answer:

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7 0
3 years ago
Read 2 more answers
If RT bisects SU, find each measure ST, RU, SV, SU,
FinnZ [79.3K]

Answer:

ST = 23

RU = 8

SV = 5

SV = 10

Step-by-step explanation:

Use the knowledge of the properties of a kite to find the measure of ST, RU, SV, and SU as shown below:

✍️Recall: Each pair of adjacent sides of a kite are congruent/equal.

ST and TU are a pair of adjacent sides.

TU = 23

✅Therefore, ST = 23.

RU and RS are a pair of adjacent sides.

RS = 8

✅Therefore, RU = 8.

✍️ Recall: the longer diagonal of a kite bisects the shorter one. This means RT divides SU into two equal parts, namely SV and UV.

Since UV = 5, therefore,

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6 0
3 years ago
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JulijaS [17]

Answer:

First answer is correct and the answer for the second question is a = 30

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3 years ago
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