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tankabanditka [31]
3 years ago
11

Jose's football weighs 7/8 pound. His football helmet weighs 5 1/6 pounds. Estimate how much more the helmet weighs than the foo

tball.
Show your work.
No trolls, reposting question for new answers.
Giving brainlyist.
Mathematics
2 answers:
Otrada [13]3 years ago
4 0

Answer:

The helmet weighs 4 7/24 pounds more than the football.

Step-by-step explanation:

Since we are trying to figure how much more something weighs than the other, it would be necessary to subtract.

First, I decided to find common factors in the two fractions, which was 24. I used that as my denominator. 7/8 translates to 21/24 and the 1/6 in 5 1/6 translates to 4/24.

Using these new equivalent values, the equation turns into 5 4/24 - 21/24.

Solving that equation gives you 4 7/24, hence my answer.

Hope this helps.

If I'm wrong, feel free to say why or what I did wrong.

PtichkaEL [24]3 years ago
3 0

Answer:

4 whole number, 7/24

Step-by-step explanation:

Thats correct i didnt had any explination because i wrote it on a paper

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Answer:

Step-by-step explanation:

(1). Maryam's answer is correct.

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Which of these is not considered Merit Aid? A) grants B) scholarships C) tuition discounts D) work-study program
scZoUnD [109]
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Read 2 more answers
You are given the information that P(A) = 0.30 and P(B) = 0.40.
Ad libitum [116K]

Answer:

1.B. No. You need to know the value of P(A and B). 2.C. Yes P(A and B) =0, so P(A or B) = P(A) + P(B).

Step-by-step explanation:

We can solve this question considering the following:

For two mutually exclusive events:

\\ A_{1}\;and\;A_{2}

\\ P(A_{1} or A_{2}) = P(A_{1}) + P(A_{2}) (1)

An extension of the former expression is:

\\ P(A_{1} or A_{2}) = P(A_{1}) + P(A_{2}) - P(A_{1} and A_{2}) (2)

In <em>mutually exclusive events,</em> P(A and B) = 0, that is, the events are <em>independent </em>one of the other, and we know the probability that <em>both events happen</em> <em>at the same time is zero</em> (P(A <em>and</em> B) = 0). There are some other cases in which if event A happens, event B too, so they are not mutually exclusive because P(A <em>and</em> B) is some number different from zero. Notice the difference between <em>OR</em> and <em>AND. The latter implies that both events happen at the same time.</em>

In other words, notice that the formula (2) provides an extension of formula (1) for those events that are not <em>mutually exclusive</em>, that is, there are some cases in which the events share the same probabilities in a way that these probabilities <em>must be subtracted</em> from the total, so those probabilities in common do not "inflate" the actual probability.

For instance, imagine a person going to a gas station and ask for checking both a tire and lube oil of his/her car. The probability for checking a tire is P(A)=0.16, for checking lube oil is P(B)=0.30, and for both P(A and B) = 0.07.

The number 0.07 represents the probability that <em>both events occur at the same time</em>, so the probability that this person ask for checking a tire or the lube oil of his/her car is:

P(A or B) = 0.16 + 0.30 - 0.07 = 0.39.

That is why we cannot simply add some given probabilities <em>without acknowledging if the events are or not mutually exclusive</em>, whereas we can certainly add the probabilities in question when we know that both probabilities are <em>mutually exclusive</em> since P(A and B) = 0.

In conclusion, knowing the events are mutually exclusive <em>does</em> provide <em>extra information</em> and we can proceed to simply add the probabilities of either event; thus, the answers are those in which <em>we need to previously know the value of P(A and B)</em>.  

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3 years ago
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Serggg [28]

Answer:

C

Step-by-step explanation:

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3 years ago
Solve for x..................
Lostsunrise [7]
7x - 9 < 12
7x < 12 + 9
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x < 21/7
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1/4x + 8 > 11
1/4x > 11 - 8
1/4x > 3
x > 3 * 4
x > 12

solution : x < 3 or x > 12
8 0
3 years ago
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