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Andrews [41]
3 years ago
11

Classify the following triangle check all that apply

Mathematics
1 answer:
Oksanka [162]3 years ago
6 0
You did not attach an image
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vector v has a horizontal vector component with magnitude 19 and a vertical vector component with magnitude 35. what is the acut
vladimir2022 [97]

9514 1404 393

Answer:

  61.5°

Step-by-step explanation:

The tangent relation is useful here. The angle is opposite the vertical side and adjacent to the horizontal side of the right triangle.

  Tan = Opposite/Adjacent

  tan(α) = 35/19

  α = arctan(35/19) ≈ 61.5°

The angle made by <em>v</em> and the positive x-axis is 61.5°.

4 0
3 years ago
What is the value of X?
zalisa [80]

i think the answer is 8

bc the small one is 4 and the big one is 6

and the other one is 6 so it must be 8

5 0
2 years ago
Read 2 more answers
Please help with this!!!
ehidna [41]

Answer:

  47.25 ft³

Step-by-step explanation:

The volume of the prism is given by the formula ...

  V = Bh . . . . . . . B is the area of the base, h is the height.

The height of the prism is given as 6 ft. The area of the base is the area of the triangular entrance. The formula for that area is ...

  A = 1/2bh . . . . . . b is the base, h is the height

Using the given values for the entrance base and height, we get ...

  A = 1/2(4.5 ft)(3.5 ft) = 7.875 ft²

Then the volume of the tent is ...

  V = (7.875 ft²)(6 ft) = 47.25 ft³

The tent volume is 47.25 cubic feet.

8 0
3 years ago
GUYS PLS HELP ME ON THIS I AM RLLY Struggling.... :(
sergiy2304 [10]
The answer to your question is 448in squared
4 0
3 years ago
Solve the simultaneous equation y-2x+1=0 and 4x^2+3y^2-2xy=7
Lapatulllka [165]

The first equation is y-2x+1=0

y=2x-1 (Equation 1)

The second equation is 4x^{2}+3y^{2}-2xy=7 (Equation 2)

Putting the value of x from equation 1 in equation 2.

we get,

4x^{2}+3(2x-1)^{2}-2x(2x-1)=7

4x^{2}+3(4x^{2}+1-4x)-4x^{2}+2x=7

by simplifying the given equation,

12x^{2}-10x-4=0

6x^{2}-5x-2=0

Using discriminant formula,

D=b^{2}-4ac

D=25-4 \times 6 \times -2 = 73

Now the formula for solution 'x' of quadratic equation is given by:

x=\frac{-b+\sqrt{D}}{2a}  and  x=\frac{-b-\sqrt{D}}{2a}

x=\frac{5+\sqrt{73}}{12}  and x=\frac{5-\sqrt{73}}{12}

Hence, these are the required solutions.

8 0
3 years ago
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