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Aleksandr-060686 [28]
3 years ago
11

Point J(-2, 1) and point K(4, 5) form the line segment jk. for the point p that partitions jk in the ratio 3:7 what is the y coo

rdinate of p
Mathematics
1 answer:
kumpel [21]3 years ago
7 0

Answer:

\frac{11}{5}

Step-by-step explanation:

Using the section formula

y_{P} = \frac{3(5)+7(1)}{3+7} = \frac{15+7}{10} = \frac{22}{10} = \frac{11}{5}

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Graph (1,1), (1,2), (1,3), (1,4)
jenyasd209 [6]

Answer:

There is not a way that I can show you how to graph it, so I will try and explain it.

Step-by-step explanation:

(1,1)

^  ^     y-axis

x-axis

You are just going right however many, and then up however many it says.

So if it's (1,1) you will go right one space, and then up one space.

Once you have all of your points on the graph, you put a line through them.

Hope this helps! :)

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3 years ago
Find the elapsed time between 5:25 pm and 11:11 pm
jekas [21]

Answer:

6 hours 26 minutes

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
He sum of two consecutive integers is â71â71. find the two integers
Crank
The two consecutive integers can be represented by x and x+1.

x+(x+1)=71

Combine like terms
2x+1=71

Subtract 1 from both sides
2x=70

Divide both sides by 2
x=35

Final answer: 35, 36
8 0
3 years ago
Can someone explain how to do this?
Over [174]

Answer:

Step-by-step explanation:

The two legs of an iscosles right triangle are equal. The sides opposite each 45 degree angle are equal.  

6^2 + 6^2 = x^2

36 + 36 = x^2

x^2 = 72

sqrt(x^2) = sqrt(72)

x = 6√2

3 0
3 years ago
Create two similar, but not equal, right triangles using A (-5,-1) and b(4,3.5)
aalyn [17]

Answer:

The attachment shows ΔBAC ~ ΔBDA

Step-by-step explanation:

You want segment AB to be part of two similar, but not congruent, triangles. One way to do that is to make AB the hypotenuse of one triangle and the leg of another.

It is convenient to construct these triangles using point M as the arbitrary midpoint of the hypotenuse of the larger triangle. (We don't know the coordinates of M—we just know it is on the perpendicular bisector of AB.) BC is a diameter of circle M, and AD is the altitude of ΔABC.

8 0
3 years ago
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