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2 years ago

This answer is the one I need to know

Mathematics

1 answer:

spayn [35]2 years ago

3 0

The answers for the problems are: 6. -18
9. 6
12. -40

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Scientific notation what is <br><br> 0.0000348 in scientific notation

trasher [3.6K]

3.48 x 10^ -5

move the decimal point back to the first number that isn't zero, if the decimal is moved right 5 spaces, it will be 10^ -5 , if a number has a zero, such as 0.000104, it would be 1.04 x 10^ -4.

8 0

3 years ago

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(a) Tom says that 1/5 + 7/20 = 8/25

mezya [45]

numerator = top part of the fraction

denominator = bottom part of the fraction

* means multiply

you can only add the numerator when the denominator is the same

cant add the denominator

denominator has to be the same

1/5 = 4/20

4/20 + 7/20 = 11/20

1 7/8 = 15/8

3/4 ÷ 15/8 =

3/4 * 8/15 =

24/60 = divide both top and bottom by 12 =

2/5

7 0

2 years ago

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Michael’s weight can be represented by the expression 72x^5. Al’s weight can be represented by the expression 9x^7.

podryga [215]

Answer:

a) $\frac{72x^5}{9x^7}$

b) $=\frac{8}{x^2}$

c), Yes; $8x^2$

Step-by-step explanation:

Michael's Weight: $72x^5$

Al's weight: $9x^7$

a) Ratio of Michael's weight to Al's weight: $\frac{72x^5}{9x^7}$

b) This ratio simplifies to: $\frac{8\times 9x^5}{9x^5\timesx^2}$

$=\frac{8}{x^2}$

c) Yes, If the exponent in each expression were negative, then we have:

Ratio of Michael's weight to Al's weight: $\frac{72x^{-5}}{9x^{-7}}$

This ratio simplifies to: $8x^{-5--7}=8x^2$

The two ratios are not the same.

3 0

2 years ago

A company that manufactures hair ribbons knows that the number of ribbons it can sell each week, x, is related to the price p pe

mel-nik [20]

Given:

The number of ribbons it can sell each week, x, is related to the price p per ribbon by the equation:

$x=1000-100p$

To find:

The selling price if the company wants the weekly revenue to be $1,600.

Solution:

We know that the revenue is the product of quantity and price.

$R=xp$

$R=(1000-100p)p$

$R=1000p-100p^2$

We need to find the value of p when the value of R is $1600.

$1600=1000p-100p^2$

$1600-1000p+100p^2=0$

$100(16-10p+p^2)=0$

Divide both sides by 100.

$p^2-10p+16=0$

Splitting the middle term, we get

$p^2-8p-2p+16=0$

$p(p-8)-2(p-8)=0$

$(p-8)(p-2)=0$

Using zero product property, we get

$p-8=0$ or $p-2=0$

$p=8$ or $p=2$

Therefore, the smaller value of p is $2 and the larger value of p is $8.

5 0

2 years ago

In 2001 there were 2,900,000 pupils in a primary school and by 2004 number had increased to 4200000 what was the percentage incr

Snowcat [4.5K]

Answer:

4.2M - 2.9M= 1300000

1.3/2.9x100= 44.83%

5 0

2 years ago

Read 2 more answers