Answer:
R = 56.6 ohms
Step-by-step explanation:
Given that,
The voltage of the battery, V = 1.7 volt
We need to find the resistance in the circuit if it uses a current of 0.03 A.
Let the resistance be R. It can be solved using Ohms law as follows :
V = IR
So, the resistance in the circuit is 56.6 ohms.
DVD weighs 6lbs and game machine weighs 14lbs, so in this case A
in my mind this is what i did...
3(gameMachines) + 5(DVD) = 72lbs
3(gameMachine) + 1 (DVD) = 48lbs
when you subtract, since there is the same number of game machines, they cancel out and your left with
4(DVD) = 24
1 DVD = 6
then just fill in DVD in one of the equations to get the weight of gameMachine
3(gameMachines) + 5(6) = 72lbs
3(gameMachines) = 42
gameMachine = 14
Answer:
13/30
Step-by-step explanation:
Add: -1/
3
+ 2/
5
= -1 · 5/
3 · 5
+ 2 · 3/
5 · 3
= -5/
15
+ 6/
15
= -5 + 6/
15
= 1/
15
For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of the both denominators - LCM(3, 5) = 15. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 3 × 5 = 15. In the next intermediate step the fraction result cannot be further simplified by canceling.
In words - minus one third plus two fifths = one fifteenth.
Subtract: 1/
2
- the result of step No. 1 = 1/
2
- 1/
15
= 1 · 15/
2 · 15
- 1 · 2/
15 · 2
= 15/
30
- 2/
30
= 15 - 2/
30
= 13/
30
For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of the both denominators - LCM(2, 15) = 30. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 2 × 15 = 30. In the next intermediate step the fraction result cannot be further simplified by canceling.
In words - one half minus one fifteenth = thirteen thirtieths.
First, Joe started the water and it was at full force. He filled it up to 9 inches. It took him 2 minutes to get to 9 inches. Then, he stopped it for 2 minutes because his mom called him to get a bar of soap. The water level was still at 9 inches when he stopped it. Then, he put the water to come down slowly because he wasn’t sure how much more he needed. He let the water go for 2 minutes. Then, he stopped the water when it was at 12 inches of water. He sat in the bath for 5 minutes until he decided he was to cold so he hopped out. The water then drained really fast. From 12 inches to 0 inches it took the bath 3 minutes.
