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3 years ago

5

A diagonal support beam is attached to the gate of a fence as shown. Which angles must be congruent in order for the top and bot

tom sides of the gate to be parallel

1 answer:

ludmilkaskok [199]3 years ago

4 0

Answer:

3 and 2

Step-by-step explanation:

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Solve<br> F = C + 32 for C

muminat

To solve an equation for a variable, you must isolate the variable on either side of the equation. To do this, simply subtract 32 from both sides of the original equation:

F ( – 32 ) = C + 32 ( – 32 )
F – 32 = C

We have proven that C is equal to (F – 32). This equation (bold) is the answer to your problem.

I hope this helps!

6 0

3 years ago

Find the unit rate. 6 2/5 revolutions in 2 2/3 seconds

Brums [2.3K]

The unit rate will be in revolutions per second. That means divide number of revolutions by number of seconds.

first convert from mixed fraction.
6 2/5 = 32/5 revolutions
2 2/3 = 8/3 seconds

32/5 ÷ 8/3
flip multiply
32/5 × 3/8 = 12/5 revolutions per second

12/5 = 2 2/5 revolutions per second

6 0

4 years ago

第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows

tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

$P(A/B)=\frac{P(A)*P(B/A)}{P(B)}$

let A be the event that the student knows the answer .

B be the event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

$P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}$

Probability that the answer is correct ,given that he knows the answer is

$P(E/A)=1$

Probability that the answer is correct ,given that he guesses it is

$P(E/B)=\frac{1}{3}$ [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability $P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}$

Substituting the values we get

$P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }$

$=\frac{6}{30}*\frac{30}{18} \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}$

Therefore , the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

#SPJ4

8 0

1 year ago

How many fewer throws travelled more than 6 3/4 meters than travelled 6 3/4 meters or less

bekas [8.4K]

Answer:

this is not a complete question cause u did not give full numbers

Step-by-step explanation:

not trying to steal points can u finish the question

4 0

3 years ago

A company’s board of directors took a random sample of 10% of the company’s employees and surveyed them about their happiness at

melisa1 [442]

D the sample mean would less closely model the population mean

6 0

3 years ago

Read 2 more answers