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3 years ago

Can you guys check this???

Mathematics

1 answer:

snow_tiger [21]3 years ago

6 0

On 4 and 6 because you are multiplying on both sides you need to flip the inequality signs
4 would be “e> -2”
6 would be “c<4”

Everything else was right
Hope this helps :D

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The town recreation committee raised money to increase the circumference of the jogger’s park, which was initially 1000 feet. It

yawa3891 [41]

Answer:C. 3000 ft

Step-by-step explanation:

First, find the radius of the circumference.

By dividing 1000 ft by 2, which is 500, and that is the radius.

Then you multiply the radius by 3, which is 1500.

Finally, you want the circumference, to find the circumference you need to multiply the radius by 2, which is 3000 ft.

That’s it.

3 0

3 years ago

Which is equivalent to V180x11 after it has been simplified completely?

inna [77]

Question:

Which is equivalent to $\sqrt{180x^{11}}$ after it has been simplified completely?

Answer:

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

Step-by-step explanation:

Given

$\sqrt{180x^{11}}$

Required

Simplify

We start by splitting the square root

$\sqrt{180x^{11}} = \sqrt{180} * \sqrt{x^{11}}$

Replace 180 with 36 * 5

$\sqrt{180x^{11}} = \sqrt{36 * 5} * \sqrt{x^{11}}$

Further split the square roots

$\sqrt{180x^{11}} = \sqrt{36} *\sqrt{5} * \sqrt{x^{11}}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{11}}$

Replace power of x; 11 with 10 + 1

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10 + 1}}$

From laws of indices; $a^{m+n} = a^m * a^n$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x^1}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x}$

Further split the square roots

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10}} * \sqrt{x}$

From laws of indices; $\sqrt{a} = a^{\frac{1}{2}}$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{10*\frac{1}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{\frac{10}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{5} * \sqrt{x}$

Rearrange Expression

$\sqrt{180x^{11}} = 6 * x^{5} * \sqrt{5} * \sqrt{x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5} * \sqrt{x}$

From laws of indices; $\sqrt{a} *\sqrt{b} = \sqrt{a*b} = \sqrt{ab}$

So, we have

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5*x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5x}$

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

<em>The expression can no longer be simplified</em>

Hence, $\sqrt{180x^{11}}$ is equivalent to $6x^{5}\sqrt{5x}$

7 0

3 years ago

Read 2 more answers

Find the sum.<br><br> (8x2 + 17x) + 6x2 =

Molodets [167]

16 + 17x + 12
17x + 28

6 0

3 years ago

When a number x is multiplied by 6, the result is 3/8.

pentagon [3]

E because 6 times .375 which is 3/8 = 16

4 0

3 years ago

Read 2 more answers

If the volume of a cube is 64 in3, how long is each side?

8_murik_8 [283]

Answer:

Step-by-step explanation:

4*4*4=16*4=64

Please mark as Brainliest! :)

Have a nice day.

5 0

3 years ago