Divide each of the following by 10, 100, and 1000: 67.8, 456.8, 531.20.

1 answer:

6 0

67.8: 6.78, 0.678, 0.0677
456.8: 45.68, 4.568, 0.4568
531.20: 53.12, 5.312, 0.5312
The pattern here is that the number of 0s there are in the digit of whatever you are dividing by, that is how many places you move the decimal place to the right. For example, by dividing 67.8 by 100, the decimal place has been moved 2 places to the right, resulting in the number 0.678

You might be interested in

It was recently estimated that females outnumber males by about three or two. If there are 1770 people in a county, how many of

max2010maxim [7]

GIVEN

1) Females outnumber males by 3 to 2.

2) There are 1770 people in the city.

SOLUTION

Let the number of males be x and the number of females y. Therefore, the total number of people can be written to be:

$x+y=1770\text{ -----------(1)}$

If there are 3 females for every 2 males, we have that:

$\begin{gathered} \frac{y}{3}=\frac{x}{2} \\ \therefore \\ x=\frac{2y}{3}\text{ ----------(2)} \end{gathered}$

We can substitute equation (2) into equation (1) and solve for y:

$\begin{gathered} \frac{2}{3}y+y=1770 \\ \frac{2y+3y}{3}=1770 \\ 5y=1770\times3 \\ 5y=5310 \end{gathered}$

Dividing both sides by 5, we have

$y=1062$

There are 1062 females in the county.

3 0

1 year ago

Which expression is equivalent to (5x^3)(2x)^3

Elanso [62]

Answer:

$\large\boxed{(5x^3)(2x)^3=40x^6}$

Step-by-step explanation:

$(5x^3)(2x)^3\qquad\text{use}\ (ab)^n=a^nb^n\\\\(5x^3)(2^3x^3)=(5x^3)(8x^3)\qquad\text{use commutative law}\\\\=(5\cdot8)(x^3x^3)\qquad\text{use}\ a^na^m=a^{n+m}\\\\=40x^{3+3}=40x^6$