Question

Factorising Quadratics

Answer 1

Quadratic formula where:
$ax ^{2} + bx + c$
$\frac{ - b + { \sqrt{b^{2} - 4ac } }}{2a}$
$\frac{ - b - \sqrt{b { }^{2} - 4ac } }{2a}$
do both do get the roots of the equation

Answer 2

Answer:

Step-by-step explanation:

A short answer is that you cannot factor this the way you are trying to do it. What to do to go on is a question. You could use the quadratic formula to get some sort of answer but if factoring is your only option, forget about it.

Here's how you can check.

• a = 12
• b = 1
• c = -15

There is a part of the quadratic solution is the sqrt(b^2 - 4*a*c). In order to be factorable, this sqrt must result in a perfect square.

sqrt(1 - 4(12)(-15) ) = sqrt( 1 - - 720) = sqrt(721)

This is anything but a perfect square. (721 does factor, however, into 7 * 103). I03 is prime. So the long and short of it is, there's no way it will factor.