Answer:
I think a number sorry trying to get points for some reason I am out.
Step-by-step explanation:
Answer:
A) Graph an quadratic equation for a parabola (x being to the power of 2), and a linear equation. Examples would be y=x² and y=x.
B) Parabolas that share the same vertex can simply have another transformation done to them. For example: y= 5x² and y=3x².
C) A line that would pass through these would be any linear graph WITHOUT a 'b' value, so a y intercept of 0. An example would be y=5x.
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7. -4(2z + 6) - 12 = 4
Simplify.
-8z - 24 - 12 = 4
Simplify.
-8z - 36 = 4
Add 36 to both sides.
-8z - 36 + 36 = 4 + 36
Simplify.
-8z = 40
Divide both sides by -8.
z = -5
8. 3/2(x - 2) - 5 = 19
Simplify.
3/2x - 3 - 5 = 19
Simplify.
3/2x - 8 = 19
Add 8 to both side.
3/2x = 19 + 8
Simplify.
3/2x = 27
Multiply both sides by 2.
3/2x · 2 = 27 · 2
Simplify.
3x = 54
Divide both sides by 3.
x = 18
~hope I helped~
Let x(2,-3) (x1 , y1) and y(-1 , 2) (x2 , y2). Using distance formula, lXYl =
![\sqrt{[2-(-1)] ^{2}+[-3-2] ^{2} } = \sqrt{1+25} = \sqrt{26} = 5.09](https://tex.z-dn.net/?f=%20%5Csqrt%7B%5B2-%28-1%29%5D%20%5E%7B2%7D%2B%5B-3-2%5D%20%5E%7B2%7D%20%20%7D%20%3D%20%20%5Csqrt%7B1%2B25%7D%20%3D%20%5Csqrt%7B26%7D%20%3D%205.09%20)
units.
