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Xelga [282]
3 years ago
5

7 red balls, 9 green balls, and 3 blue balls you draw two balls from the urn but replace the first ball before drawing the secon

d find the probability that the first ball is red and the second is heee
Mathematics
1 answer:
Vlad1618 [11]3 years ago
5 0

Answer:

Step-by-step explanation:

With replacement of the first ball

P(first ball is red and the second is green) =7/19 * 9/19= 63/361=.175

without replacement (14 total balls in the urn on the second draw)

P(first ball is red and the second is green) =7/18 * 9/18= 63/324=.194

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Answer:

Given:

  • Total balls = 10
  • Black balls = 3
  • White balls = 7

⇒ P(black ball) = 3/10 = 0.3

⇒ P(white ball) = 7/10 = 0.7

If one ball is chosen at random and <u>replaced</u>, the probabilities do not change between the first and second ball.

Let event D = first ball is black

Let event S = second ball is black

P(D) = 0.3

P(S) = 0.3  (since the first ball is replaced)

⇒ P(D ∩ S) = P(D) × P(S)

                   = 0.3 × 0.3

                   = 0.09

For Independent Events we know that:  P(A ∩ B) = P(A) × P(B)

Therefore, as P(D ∩ S) = P(D) × P(S) the events are independent.

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Digiron [165]

Answer: c. E2 - 21

Step-by-step explanation:

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Now, e squared=E² and twenty-one=21

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Answer:

84%

Step-by-step explanation:

Joey gives 21 correct answers out of 25 questions on a quiz.

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Now, percentage of x out of y is given by the simple expression \frac{x}{y} \times 100%.

Hence, the percentage of correct answer given by Joey is given by  

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