Answer:
The area of the walking path = 3,371 ft²
Explanation:
The complete Question is presented in the attached image to this solution
Note that the walking path consists of straight paths and curved paths.
The straight path is strictly squares, with 9 of them on both sides (top and bottom)
Area of the straight path = 18 × area of one square = 18 × 10² = 1800 ft²
For the curved path, note that their areas is the area between two semi circles.
Smaller semicircle has a radius of r = 20 ft.
Larger semicircle has a radius of R = 30 ft.
Area between the two semicircles = (Area of larger semicircle) - (Area of smaller semicircle)
= (πR²/2) - (πr²/2)
= (π×30²/2) - (π×20²/2)
= 785.4 ft²
But note that there are two of those curved paths, hence, area of the curved paths
= 2 × 785.4 = 1570.8 ft²
Total area of the walking path = (Area of straight path) + (Area of curved path)
= 1800 + 1570.8 = 3370.8 ft² = 3371 ft² to the nearest whole number.
Hope this Helps!!!
Answer:
In the books of Eisler Corporation :
Cash ( 2,000 x 1,000 x 101 %) A/c Dr. 2,020,000
Discount on Bonds Payable A/c Dr. $59,216
To Bonds Payable 2,000,000
To Paid-in Capital : Stock Warrants 79,216
Workings:
Bond issue proceeds proportionately allocated to bonds:
= 1,940,784.31
Discount on bonds payable = $ 2,000,000 - $1,940,784
= $59,216