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anyanavicka [17]
3 years ago
12

Write a real-word problem that involves classifying a quadrilateral. Then solve the problem.

Mathematics
1 answer:
natima [27]3 years ago
3 0
Hello there!

Let me try :)

You decided to tell someone to make a book for you. You need to tell him what shape you would like the book to have. But since you want it to be quadrilateral, you need to go there and make sure that the person is doing it correctly. So that they don't give you the book with a shape of a triangle, then you would have problem to add it on your shelf because it wouldn't look interesting.

Note: A quadrilateral is defined as a polygon (a closed shape) with 4 sides, so any shape/object with four sides can be considered a quadrilateral.


I hope this helps!
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The number -13 can be classified as:
pogonyaev
<h3>Answer: Choice B) real and integer</h3>

Explanation:

The set of integers is {..., -3, -2, -1, 0, 1, 2, 3, ...} basically its the set of positive and negative whole numbers, including 0 as well. The set of whole numbers is {0, 1, 2, 3, 4, ...} so any positive number that does not a fractional or decimal part. The value 0 is included in the set of whole numbers. The natural numbers is {1, 2, 3, 4, ...} so it is the set of whole numbers but we kicked out 0 from this set. The set of natural numbers is also called the set of counting numbers.

If we take any two integers and divide them then you'll get a rational number. You cannot have zero in the denominator, but you can have any other integer. For example,  2 and 3 divide to get the fraction 2/3 which is a rational number. Numbers that we cannot express as a fraction of two integers are said to be irrational. An example of this is pi = 3.14 which is irrational. We cannot write pi as a ratio of two integers. One approximation is pi = 22/7, but this doesn't represent pi exactly. Any integer itself is rational. Something like -13 can be written as -13/1, so we cannot say -13 is irrational. That rules out choice A. Choice C is ruled out because negative numbers aren't natural numbers. The same can be said about -13 not being part of the whole number set {0, 1, 2, 3, 4, ...} so choice D is also false.

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