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Oliga [24]
3 years ago
10

What is the base....

Mathematics
1 answer:
olga2289 [7]3 years ago
3 0

Answer:

Step-by-step explanation:

-5x the base

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Drone INC. owns four 3D printers (D1, D2, D3, D4) that print all their Drone parts. Sometimes errors in printing occur. We know
USPshnik [31]

Answer:

Step-by-step explanation:

Hello!

There are 4 3D printers available to print drone parts, then be "Di" the event that the printer i printed the drone part (∀ i= 1,2,3,4), and the probability of a randomly selected par being print by one of them is:

D1 ⇒ P(D1)= 0.15

D2 ⇒ P(D2)= 0.25

D3 ⇒ P(D3)= 0.40

D4 ⇒ P(D4)= 0.20

Additionally, there is a chance that these printers will print defective parts. Be "Ei" represent the error rate of each print (∀ i= 1,2,3,4) then:

P(E1)= 0.01

P(E2)= 0.02

P(E3)= 0.01

P(E4)= 0.02

Ei is then the event that "the piece was printed by Di" and "the piece is defective".

You need to determine the probability of randomly selecting a defective part printed by each one of these printers, i.e. you need to find the probability of the part being printed by the i printer given that is defective, symbolically: P(DiIE)

Where "E" represents the event "the piece is defective" and its probability represents the total error rate of the production line:

P(E)= P(E1)+P(E2)+P(E3)+P(E4)= 0.01+0.02+0.01+0.02= 0.06

This is a conditional probability and you can calculate it as:

P(A/B)= \frac{P(AnB)}{P(B)}

To reach the asked probability, first, you need to calculate the probability of the intersection between the two events, that is, the probability of the piece being printed by the Di printer and being defective Ei.

P(D1∩E)= P(E1)= 0.01

P(D2∩E)= P(E2)= 0.02

P(D3∩E)= P(E3)= 0.01

P(D4∩E)= P(E4)= 0.02

Now you can calculate the probability of the piece bein printed by each printer given that it is defective:

P(D1/E)= \frac{P(E1)}{P(E)} = \frac{0.01}{0.06}= 0.17

P(D2/E)= \frac{P(E2)}{P(E)} = \frac{0.02}{0.06}= 0.33

P(D3/E)= \frac{P(E3)}{P(E)} = \frac{0.01}{0.06}= 0.17

P(D4/E)= \frac{P(E4)}{P(E)} = \frac{0.02}{0.06}= 0.33

P(D2)= 0.25 and P(D2/E)= 0.33 ⇒ The prior probability of D2 is smaller than the posterior probability.

The fact that P(D2) ≠ P(D2/E) means that both events are nor independent and the occurrence of the piece bein defective modifies the probability of it being printed by the second printer (D2)

I hope this helps!

8 0
3 years ago
What is the awnser to this equation
Scorpion4ik [409]

Answer:

14..........................

7 0
3 years ago
How can you find the area of a shape with fractional or decimal side lengths?
SOVA2 [1]

Answer:

You convert the fractions to a decimal, nut the rest is still the same

Step-by-step explanation:

3 0
3 years ago
The diameter of a circle is 8 miles.What is the circle’s radius?
zmey [24]

Answer:

4 miles

Step-by-step explanation:

because radius is 2 times of circle

8 0
3 years ago
Simplify (ignore my garbage camera quality ....)
monitta

Answer:

C. 3

Step-by-step explanation:

Given expression is:

({3^{\frac{1}{7}})^7

We know that the rules of exponents are used to solve these kind of questions.

When there is exponent on exponent like in this question 1/7 has an exponent of 7 , the exponents are multiplied.

So,

=3^{(7*\frac{1}{7} )}

The 7's will be cancelled out and remaining power will be 1

=3^1\\=3

Hence, option C is correct ..

5 0
3 years ago
Read 2 more answers
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