20,0000000000000000000000 I can’t help with this I dropped out of school
Answer:
OB) The mode does not change
Answer:
about 78 years
Step-by-step explanation:
Population
y =ab^t where a is the initial population and b is 1+the percent of increase
t is in years
y = 2000000(1+.04)^t
y = 2000000(1.04)^t
Food
y = a+bt where a is the initial population and b is constant increase
t is in years
b = .5 million = 500000
y = 4000000 +500000t
We need to set these equal and solve for t to determine when food shortage will occur
2000000(1.04)^t= 4000000 +500000t
Using graphing technology, (see attached graph The y axis is in millions of years), where these two lines intersect is the year where food shortages start.
t≈78 years
Answer:
B
Step-by-step explanation:
Equation of line 1:
Choose two points : (-1, 0) & (0,2)
y -intercept = b = 2
y = mx+ 2
Plugin the values of the points ( -1 , 0) in the above equation
0 = -1m + 2
-2 = -m
m = 2
Equation of line 1 : y = 2x + 2
Equation of line 2:
(5,0) & (0,5)
y-intercept = b = 5
y = mx +b
y = mx + 5
Plugin the value of points (5 , 0) in the above equation
0 = 5m + 5
-5 = 5m
-5/5 = m
m = -1
Equation of line 2: y = -x + 5
Conclusion: 2x + 2 = -x + 5
Step-by-step explanation:
=== [ -3(x-10)/4] + 2 = 11
==> [( -3x + 30 + 8)/4 = 11
==> -3x = 44 - 38
==> -3x = 6
==> -x = 6/3
==> x = -2
