Question

There are 11 paintings at an art show. Four of them are chosen randomly to display in the gallery window. The order in which they are chosen does not matter. How many ways are there to choose paintings? A. 7920 B. 330 C.44 D. 121

Answer 1

Answer:

The correct answer is option B.  330

Step-by-step explanation:

It is given that,There are 11 paintings at an art show. Four of them are chosen randomly to display in the gallery window.

To find the possible ways

There are total 11 paintings.

We have to choose 4 of them

Possible number of ways = 11C₄

 = (11 * 10 * 9 )/(1 * 2* 3 * 4)

 = 330 ways

Therefore the  correct answer is option B.  330

Answer 2

Answer:

B. 330

Step-by-step explanation:

The question indicates the order doesn't matter, so it's a combination and not a permutation.

The combinations are calculated using this formula:

$C(n,r) = \frac{n!}{r! (n-r)!}$

In this case we have a population of 11 (n = 11) and a selection of 4 (r=4), so...

$C(11,4) = \frac{11!}{4! (11-4)!} = 330$

So, there are 330 different combinations that can be made of 4 paintings out of a selection of 11.