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2 years ago

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There are 11 paintings at an art show. Four of them are chosen randomly to display in the gallery window. The order in which the

y are chosen does not matter. How many ways are there to choose paintings? A. 7920 B. 330 C.44 D. 121

2 answers:

VMariaS [17]2 years ago

8 0

Answer:

The correct answer is option B. 330

Step-by-step explanation:

It is given that,There are 11 paintings at an art show. Four of them are chosen randomly to display in the gallery window.

<u>To find the possible ways</u>

There are total 11 paintings.

We have to choose 4 of them

Possible number of ways = 11C₄

= (11 * 10 * 9 )/(1 * 2* 3 * 4)

= 330 ways

Therefore the correct answer is option B. 330

Vinil7 [7]2 years ago

3 0

Answer:

B. 330

Step-by-step explanation:

The question indicates the order doesn't matter, so it's a combination and not a permutation.

The combinations are calculated using this formula:

$C(n,r) = \frac{n!}{r! (n-r)!}$

In this case we have a population of 11 (n = 11) and a selection of 4 (r=4), so...

$C(11,4) = \frac{11!}{4! (11-4)!} = 330$

So, there are 330 different combinations that can be made of 4 paintings out of a selection of 11.

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