Answer:
They are: area of sector and area of triangle
Step-by-step explanation:
Area of segment=area of sector - area of triangle
So we need both the area of sector and area of triangle to calculate for the area of a segment
Answer:
A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable. One absolute rule is that the first constant "a" cannot be a zero.
Step-by-step explanation:
Answer:
7
Step-by-step explanation:
1/2<u>(48/6)</u> - 2 + 5
<u>1/2(8)</u> - 2 + 5
<u>4 - 2</u> + 5
<u>2 + 5</u>
7
Answer:
wrerv werw
Step-by-step explanation:3
r wer wer w e3r
Answer:
Step-by-step Explanation:
Extend the sides AD and BP. This creates 2 congruent triangles using ASA. Triangles CBP and adjacent triangle are also congruent bc of ASA. This makes 3 congruent triangles (transitivity). That means just finding the area of the constructed large triangle, you find the area of the parallelogram. Since point P is the midpoint of B_, P_ also equals 9. Using the formula for the area of a triangle, and Pythagorean theorem (9-12-15), 12*18/2=108, which is the area of the parallelogram.
