Answer:
10 small boxes and 12 large boxes
Step-by-step explanation:
Let x = number of large boxes
Let y = number of small boxes
We are told that;
volume of each small box = 6 cubic feet
volume of each large box = 22 cubic feet.
Total volume = 324 ft³
Thus;
6x + 22y = 324 - - - (eq 1)
We are told that 22 boxes of paper were shipped.
Thus; x + y = 22 - - - (eq 2)
Making x the subject in eq 2 gives;
x = 22 - y
Put 22 - y for x in eq 1;
6(22 - y) + 22y = 324
132 - 6y + 22y = 324
16y = 324 - 132
16y = 192
y = 192/16
y = 12
So, x = 22 - 12 = 10
The zeros of the given functions are shown on the attached picture.
Answer:
3√(22) + 7
Step-by-step explanation:
The way this is worded can be interpreted two different ways so just to cover the bases, I'll do both. I'm confident they are asking for way 1 though because it wants you to simplify the expression, not evaluate. Way 2 gives you a solution rather than an exact equation.
<u>Number 1</u>
√(6) x √(33) + 7
= √(6 x 33) + 7
= √(198) + 7
= √(9 x 22) + 7
= 3√(22) + 7
<u>Number 2</u>
√(6) x √(33 + 7)
= √(6) x √(40)
= √(6) x (4√(10))
= 4√(60)
= 8√(15)
Answer:
28m⁷n⁵
Step-by-step explanation:
You would first multiply 14 by 2. You would then multiply (which is really addition when it comes to exponents) your like-term exponents.
(14m²n⁵)(2m⁵) =28m⁷n⁵
14(2) = 28
m² + m⁵=m⁷
n⁵ + 0 = n⁵
Let n be a number of balls: n = 14
In one pan you have 8 balls: 8n
In the other pan you have the rest of balls (14 - 8 = 6) along with a <span>weight of 20 grams = 6n + 20
So the pans are balanced:
8n = 6n + 20
Now, just solve the equation:
8n - 6n = 20
2n = 20
n = 20/2
n = 10
So, you know that a ball weights 10 grams.</span>
