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Leya [2.2K]
3 years ago
14

The altitude a (in feet) of a plane t minutes after liftoff is given by a=3,400t +600 . How many minutes after liftoff is the pl

ane at an altitude of 21,000 feet?
Mathematics
1 answer:
grin007 [14]3 years ago
3 0

Answer:

6 minutes

Step-by-step explanation:

a=3400t+600 substitute 21000 for a

21000=3400t+600 subtract 600 from both sides

20400=3400t divide by 3400

6=t

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A recent study at UGA (March 5, 2008) suggests that students with cell phones may take more risks than students that do not have
Ira Lisetskai [31]

Answer:

(a) -2.8

b) (1) Reject H0: p = 0.50 in favor of HA: p < 0.50; there is sufficient evidence to conclude that less than half of all UGA female students who, if they had a cell phone, would be willing to walk somewhere after dark that they would normally not go.

Step-by-step explanation:

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

H0: p = 0.50

This means that:

\mu = 0.5, \sigma = \sqrt{0.5*0.5} = 0.5

In a random sample of 305 UGA female students, 128 responded that, if they had a cell phone, they would be willing to walk somewhere after dark that they would normally not go.

This means that n = 305, X = \frac{128}{305} = 0.4197

a) Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.4197 - 0.5}{\frac{0.5}{\sqrt{305}}}

z = -2.8

Pvalue:

We are testing the hypothesis that the proportion is less than 0.5, which means that the pvalue of the test is the pvalue of z = -2.81.

Looking at the z-table, z = -2.8 has a pvalue of 0.0026

(b) What is the correct conclusion for this hypothesis test at the 0.05 level of significance?

0.0026 < 0.05, which means that we reject the null hypothesis, that the proportion is 0.5, and accept the alternate hypothesis, that the proportion is less than 0.5, option (1).

6 0
3 years ago
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