I heard this was the place to come for help! I guess I heard wrong This question has been out here for over an hour 4x-x/4+x+1/3
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The given highest power of <em>x</em> in the given function, y = 4·x + 2, is 1,
therefore, the graph of the function is a straight line.
The statement that correctly compares the function shown on the graph
with the function; y = 4·x + 2 is; <u>C. The function shown on the graph has a </u>
<u>smaller rate of change but a higher starting point</u>.
Reasons:
The given function is; y = 4·x + 2
Comparing with the equation for a straight line; y = m·x + c, we have;
The rate of change or slope, m = 4
The y-intercept, starting point, c = 2
Two points on the function shown on the graph are; (0, 4), and (-2, -2)
The slope of the given graph is therefore;
The rate of change of the graph, m = 3
The equation of the graph is therefore;
y - 4 = 3·(x - 0)
Which gives;
y = 3·x + 4
The y-intercept, starting point of the graph, is therefore, c = 4
Which gives;
The function shown on the graph has a higher starting point but a smaller rate of change than the given function.
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