Answer: Option 'C' is correct.
Step-by-step explanation:
Since we have given that

Now, we will find the quotient by factoring the numerator:

Now, we will factor it again:

At last we get our factorised form :

Hence, Option 'C' is correct.
Answer:
3x(3x+5)(x-2)
Step-by-step explanation:

Hope this helps!
12: 1.8= 20/3. => the answer is 20/3 miles
Subtraction: 18 - b
Addition: 18 + b
Multiplication: 18b, or 18 x b
Division: 18 divided (My keyboard doesn't have a division sign?) by b
Hope this helped.