Answer:
4.76% probability that a randomly selected person from the population has a positive test result
Step-by-step explanation:
We have these following probabilities:
4% probability of having the disease.
If a person has a disease, 95% probability of a positive test.
100-4 = 96% probability a person does not have the disease.
If a person does not have the disease, 1% probability of a positive test.
What is the probability that a randomly selected person from the population has a positive test result
95% of 4% and 1% of 96%. So
p = 0.95*0.04 + 0.01*0.96 = 0.0476
4.76% probability that a randomly selected person from the population has a positive test result
Answer:
x<32 (i thik is what you want)
Step-by-step explanation:
if x/8+1<3
x has to be less the 4*8, which is 32.
so x<32
Answer:
-16/4 + 11/4
then u find common mutiples
This should be the data:
1ML
<span>100L </span>
<span>5 million nL </span>
<span>1GL </span>
<span>50 mL </span>
<span>1cL </span>
<span>1mL
</span>
Below is the answer:
the conversion into litres are next to the order of volume.
<span>1. 1GL (10^9) </span>
<span>2. 1ML (10^6) </span>
<span>3. 100L (100) </span>
<span>4. 50mL (50*10^-3)=0.05 </span>
<span>5. 1cL (10^-2) </span>
<span>6. 5 million nL [(5*10^6)*(10^-9)]=0.005 </span>
<span>7. 1mL (10^-3) </span>
Answer:
4th one
Step-by-step explanation: