Bob had 18 crackers Sam eat 1/6 of the crackers and sue ate 1/3 of the crackers. how many crackers did Bob have left
2 answers:
We can add 1/6 & 1/3 together to find out the total amount of crackers that were eaten: 1/6 + 1/3 (Find the Common Denominator. In this case it is 6.) = 1/6 + 2/6 = 3/6 (Now find the Lowest Terms. Both 6 & 3 divide into 3) = 1/2 (In Lowest Terms) This means that 1/2 of the Crackers have been eaten. 1/2 of 18 = 9 Therefore, Bob has 9 Crackers left.
The first thing to do is make both fractions over 6: 1/3 = 2/6 Sue at 2/6 of the crackers. Now we can add the fractions: 2/6 + 1/6 = 3/6 The next thing to do is cancel down the fraction. 3/3 = 1 6/3 = 2 3/6 = 1/2 Now that we know that half of the crackers have been eaten, we halve the total amount: 18 X 1/2 = 18 / 2 = 9 Bob had 9 crackers left.
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