The work done is 400 J
Explanation:
The work done by you in pushing the box along the slope is given by
where
F is the magnitude of the force applied
d is the distance covered by the box along the slope
Here we have the following:
F = 200 N is the magnitude of the force applied
is the distance covered, where
h = 1 m is the vertical rise
is the slope of the plane
Substituting and solving, we find
Learn more about work:
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<span>To calculate the magnitude of the initial momentum of the car in this situation you have to multiple the mass of the blue car times the speed. The mass, 468kg, times the speed, 21 m/s, equals 9828. This means the magnitude of the initial momentum of the blue car in the situation is 9828kg per m/s. In this case, and in simple terminology, the magnitude measures how big something is. So the magnitude of the momentum is just the measurement of how big the initial moment of the car is.</span>
Answer:
D. 2.0 kg m/s
Explanation:
Momentum after = momentum before
p = (0.500 kg) (4.0 m/s) + (1.0 kg) (0 m/s)
p = 2.0 kg m/s
Answer:
B
Explanation:
Formula
Mechanical advantage = length of the ramp / height
Givens
Length of the ramp = 8
Mechanical advantage = 2
height = ?
Solution
2 = 8feet / height Multiply both sides by height
2* height = 8 feet * height / height Combine
2* height = 8 feet Divide by 2
2*height/2 = 8 feet/2
height = 4 feet.
Answer:
408.33watts
Explanation:
Power is expressed according to the formula
Power = work done/time
Power = force × distance/time
Power = Force× velocity
Find the force
F = mv/t
F = 600×1.75/4.5
F = 1050/4.5
F=233.33N
Get the power
Power = 233.33×1.75
Power = 408.33watts
Hence the average power of the elevator motor during this period is 408.33m/s
