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SpyIntel [72]
2 years ago
13

Sally and Suzy are moving into their first college dorm together. They are loading all their furniture onto a truck with a ramp

that is 8 feet long.
How far is the back of the truck off the ground if the mecanical advantage of this ramp is 2?


A) .25 ft
B) 4 ft
C) 8 ft
D) 16 ft​
Physics
1 answer:
Ksenya-84 [330]2 years ago
6 0

Answer:

B

Explanation:

Formula

Mechanical advantage = length of the ramp / height

Givens

Length of the ramp = 8

Mechanical advantage = 2

height = ?

Solution

2 = 8feet / height                                  Multiply both sides by height

2* height = 8 feet * height / height      Combine

2* height  = 8 feet                                 Divide by 2

2*height/2 = 8 feet/2                              

height = 4 feet.

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What is the concentration of H+ ions at a pH = 2? mol/L What is the concentration of OH– ions at a pH = 2? mol/L What is the rat
densk [106]

Answer:

In Step 5, you will calculate H+/OH– ratios for more extreme pH solutions. Find the concentration of H+ ions to OH– ions listed in Table B of your Student Guide for a solution at a pH = 2. Then divide the H+ concentration by the OH– concentration. Record these concentrations and ratio in Table C.

What is the concentration of H+ ions at a pH = 2?

0.01   mol/L  

What is the concentration of OH– ions at a pH = 2?

0.000000000001   mol/L  

What is the ratio of H+ ions to OH– ions at a pH = 2?

10,000,000,000 : 1

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I LITERALLY spent 40 MINUTES trying to figure out this question, so please, use my VERY CORRECT answers!

I hope this helps!

4 0
3 years ago
a plane is flying due east in still air at 395 km/h. suddenly, the plane is hit by wind blowing at 55km/h toward the west. what
Sphinxa [80]
Let's be clear:  The plane's "395 km/hr" is speed relative to the
air, and the wind's "55 km/hr" is speed relative to the ground.

Before the wind hits, the plane moves east at 395 km/hr relative
to both the air AND the ground.

After the wind hits, the plane still maintains the same air-speed.
That is, its velocity relative to the air is still 395 km/hr east.
But the wind vector is added to the air-speed vector, and the
plane's velocity <span>relative to the ground drops to 340 km/hr east</span>.

6 0
3 years ago
A wildebeest and chicken participate in a race over a 2.00km long course. the wildebeest travels at a speed of 16.0m/s and chick
Nezavi [6.7K]

Answer:

(a)  The distance of the chicken from the finish line is 62.5 m

(b) The stationary time of the wildebeest is 675 s

Explanation:

Given;

total distance traveled by wildebeest and chicken, d = 2 km = 2000 m

speed of the wildebeest, v_w = 16 m/s

speed of the chicken, v_c = 2.5 m/s

Time for wildebeest to finish the race without stopping, 2000 / 16 = 125 s

Time for chicken to finish the race without stopping, 2000/2.5 = 800 s

(b) for how long in time (in s) was the wildebeest stationary?

t(stationary) = t(chicken) - t(wildebeest)

t = 800s - 125 s

t = 675 s

(a) how far (in m) is the chicken from the Finish Line when the wildebeest resume the race?

The time taken for the wildebeest to run 1.6 km (1600 m) is given by;

t = 1600 / 16 = 100 s

The total time spent by the wildebeest before it resumed the race = stationary time + 100s

t (total) = 675 s + 100 s = 775 s

Distnace traveled by the chicken when the wildebeest resumed the race = 2.5m/s x 775s = 1937.5 m

Thus, the distance of the chicken from the finish line = 2000 m -  1937.5 m

the distance of the chicken from the finish line = 62.5 m

7 0
3 years ago
As Clinton walks he pushes his shoe against the track.
Valentin [98]

Answer:A:The track pushes back on Clinton's shoe with the same force.

Explanation:According to Newton's third law of motion, for every action force there is an equal and opposite reaction force. In this case, the action force is Clinton's shoe pushing on the track. As this happens, there is an equal and opposite reaction force in which the track pushes back on Clinton's shoe with the same force.

4 0
3 years ago
A toy cart is pulled a distance of 6.00 m in a straight line across the floor. The force pulling the cart has a magnitude of 20.
aivan3 [116]

Answer:

W = 95.8J

Explanation:

Given

S = 6.00m

F =20.0N

Theta = 37°

W = FSCos(theta)

W = 20×6.0×Cos(37)

W = 95.8J

8 0
3 years ago
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