X+Y=10
XY=-300
Solve for one of the variables
X=10-Y
Plug into the other equation
Y(10-Y)=-300
Now, you have a quadratic...
-y²-10y+300=0
I would multiply everything by -1, so there's no coefficient on y²
y²+10y-300=0
And solve...
-10±√(100-4(-300))
----------------------------
2
Y=-5±5√(13)
Plug back onto original equation...
X+(-5±5√(13))=10
X±5√(13)=15
X=15±5√(13)
Note: There are 2 sets of answers, keep the negatives with the negatives, and the positives with the positives when dealing with the ±.
Answer:
-2.5
Step-by-step explanation:
5b - b - 1 ≥ -11
4b - 1 ≥ -11
+1 +1
4b ≥ -10
4/4 -10/4
b ≥ -2.5
Answer:
Side a is 35/5=7 inches long
Side b is 30/5=6 inches long
Side c is 15/5=3 inches long
38,428 - 21,728= $16,700 left over
