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2 years ago

Is p-6 a quadratic trinomial

Mathematics

1 answer:

VladimirAG [237]2 years ago

5 0

Answer:

No, it is a linear binomial

Step-by-step explanation:

Since, the exponent of p in p - 6 is one and it has only two terms, therefore it is not a quadratic trinomial but a linear binomial.

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What is the missing number<br> 7 x ( ? x 9) = 63

GrogVix [38]

The ? is 1.

7*(9*1)=63

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3 years ago

Generate two numerical patterns

Klio2033 [76]

Answer:

vvv

Step-by-step explanation:

2,4,6,8,10

Pattern Rule:Add 2

1,2,4,8,16

Pattern:Multiply by 2

Sorry these were simple.

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2 years ago

ABCDEFGHIJ is a regular decagon.

Vilka [71]

Answer:

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Step-by-step explanation:

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2 years ago

A country is considering two income tax rates. Geoffrey is comparing what his tax bill would be under each plan. Under plan A, h

worty [1.4K]

98000*0.15 is how you would find out how much he has to pay for tax, which is 14700. since you didn't post plan b, this is all i can do.

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2 years ago

Read 2 more answers

In a survey of adults aged 57 through 85 years, it was found that 86.6% of them used at least one prescription medication. Com

OleMash [197]

Answer:

a) 272 used at least one prescription medication.

b) The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).

Step-by-step explanation:

Question a:

86.6% out of 3149, so:

0.866*3149 = 2727.

272 used at least one prescription medication.

Question b:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 3149, \pi = 0.866$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 - 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.856$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 + 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.876$

For the percentage:

0.856*100% = 85.6%

0.876*100% = 87.6%.

The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).

7 0

2 years ago