From 2000 to 2011, there are 11 years. From the given function, we can calculate the profit for a small business at the end of 2011 by substituting 11 to the x of the given equation.
y = (30,000)(1.06)(11)
y = 349,800
Thus, the profit at the end of 2011 is approximately $349,800.
Answer:
He walks 1,060 miles on the tremil in one year.
Step-by-step explanation:
4*5=20*53=1,060
There are 53 sometimes 52 weeks in a year,2020 wise 53 so 53*20=1,060 miles.
It would b 9 x (-3^(x-1))
Answer:
after 10 months
Step-by-step explanation:
Let x be the number of months and y be the amount they still owe.
Sin Ian borrows $1000 from his parents, then the y-intercept b= 1000 since he owes $1000 when x = 0. He pays them back $60 each month The slope is then m = -60 . Substituting in b = 1000 and m = -60 into the slope-intercept form of a line then gives y= mx + b=-60x +1000.
Sin Ken borrows $600 from his parents, then the y-intercept b = 600 since he owes $600 When x= 0. He pays them back $20 per month so the amount he owes decreases $20 each month. The slope is then m = -20 . Substituting in
b= 600 and m = -20 into the slope-intercept form then gives y = mx +b = -20x + 600.
They will owe the same amount when they have the same y-coordinate. Therefore -60x+ 1000= y= -20x+600. Solve this equation for x:
-60x+ 1000 = -20x+ 600
1000 = 40x+ 600
400 = 40x
10=x
They will then owe the same amount after 10 months.
To find this, use the distance formula. D= square root over... (x2-x1)^2+ (y2-y1)^2. Now plug in your coordinates.
D= square root... (4- -7)^2+ (-5-3)^2. Simplify. 4- -7=11 (two neg= positive) -5 -3= -8. So,
D= square root... 11^2+ -8^2. Simplify. 11^2= 121. And -8^2=64. Now just take the square root after adding. 121+64= 185. And the square root of 185 isn’t a whole number, so your final answer is D= (square root over) 185. Hope this helps
