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2 years ago

Plz someone help me on this one I need help !

Mathematics

2 answers:

Gennadij [26K]2 years ago

6 0

23(13)=(23)(13)=(2)(1)(3)(3)=29(Decimal: 0.222222)

Monica [59]2 years ago

4 0

2/9 is the answer for your question

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which statement is true about the equation 3/4z-1/4z+3=2/4z+5. It has no solution. It has one solution. It has two solutions. It

kozerog [31]

3/4z - 1/4z + 3 = 2/4z + 5
3/4z - 1/4z - 2/4z = 5 - 3
2/4z - 2/4z = 2
0 ≠ 2
----------------------------
It has no solution.

3 0

3 years ago

Read 2 more answers

b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.

Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

Step-by-step explanation:

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ $2x$

The third box contained two more pounds than the first box i.e.

⇒ $x+2$

The last box contained one-fourth the amount in the second box i.e.

⇒ $(\frac{1}{4})2x = \frac{x}{4}$

Therefore , Sum of pounds of candy are :

⇒ $\frac{x}{2} +x+2+2x+x=65$

⇒ $\frac{x}{2} +4x=63$

⇒ $\frac{9x}{2}=63$

⇒ $x=63(\frac{2}{9} )$

⇒ $x=14$

Therefore , Candy in each box is :

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

8 0

3 years ago

Midpoint of the segment between the points (−5,13) and (6,4)

Leokris [45]

Answer: $(0.5,8.5)$

Step-by-step explanation:

We need to use the following formula to find the Midpoint "M":

$M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Given the points (-5,13) and (6,4) can identify that:

$x_1=-5\\x_2=6\\\\y_1=13\\y_2=4$

The final step is to substitute values into the formula.

Therefore, the midpoint of the segment between the points (-5,13) and (6,4) is:

$M=(\frac{-5+6}{2},\frac{13+4}{2})\\\\M=(\frac{1}{2},\frac{17}{2})\\\\M=(0.5,8.5)$

6 0

2 years ago

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Can someone please help me answer this?

sammy [17]

Answer:

Not clear enough

Step-by-step explanation:

please resend the question and make it more clear and readable

8 0

3 years ago

For the school play 40 rows of chairs are set up there are 22 chairs in each row how many chairs are there

liq [111]

If you had one row, you would have 22 chairs.

If you had two rows, you would have 22+22=44 chairs.

If you had three rows, you would have 22+22+22 chairs, or 66 chairs.

See the pattern?

If you had 40 rows, you would add 22 40 times, or 22*40=880 chairs.

Hope this helps!

6 0

3 years ago

Read 2 more answers