Answer:
The distance between 12m-sides is 
.
Step-by-step explanation:
It is given that the parallelogram has sides 10m and 12m and an angle of 45°.
Draw an altitude from one 12m side to another 12 m side as shown in below figure.
The opposite angles of parallelogram are same. Two angles are obtuse angles and two are acute angle.
Since angle C is acute angle therefore it must be 45 degree.
Therefore the distance between 12m-sides is .
Answer:
<em>x = -10</em>
Step-by-step explanation:
(9/2)(8 - x) + 36 = 102 - (5/2)(3x + 24)
Multiply both sides by 2.
9(8 - x) + 2 * 36 = 2 * 102 - 5(3x + 24)
Distribute on both sides.
72 - 9x + 72 = 204 - 15x - 120
Combine like terms on each side.
144 - 9x = 84 - 15x
Subtract 144 from both sides. Add 15x to both sides.
6x = -60
Divide both sides by 6.
x = -10
The answer is $160. You have to subtract 200 from 20%
Answer:
51.7°
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you that ...
Tan = Opposite/Adjacent
tan(D) = EF/FD = 95/75
D = arctan(95/75)
∠D ≈ 51.7°
Answer:( 3, 4)
Step-by-step explanation: :)
