3 years ago

Also need help with this one

1 answer:

8 0

Let the width of table B be w, and since area of table A = area of table B, then 6 2/3 x 3 1/2 = 4 1/4 x w [this is the required equation]
20/3 x 7/2 = 17/4 w
17/4 w = 70/3
w = 70/3 / 17/4 = 70/3 x 4/17 = 280/51 = 5 25/51

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Answer:

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Step-by-step explanation:

Given expression is $\frac{2x^2+8x}{(x+4)(x^2-9)}$

To find for what value of x is undefined in the given expression :

$\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x(x+4)}{(x+4)(x^2-9)}$

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$\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x}{x^2-9}$

If we put x=3 in the above expression we get

$\frac{2x}{x^2-9)}=\frac{2(3)}{3^2-9}$

$=\frac{6}{9-9}$

$=\frac{6}{0}$

Therefore $\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{6}{0}$

The value at x =3 is undefined for the given expression

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