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soldi70 [24.7K]
3 years ago
14

-5(n - 5) -5 what is the n?

Mathematics
2 answers:
Savatey [412]3 years ago
8 0

Answer:

-5n+20 that is the Solution

scoray [572]3 years ago
6 0

Answer:

-5 x (4-n)

Step-by-step explanation:

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Nataliya [291]

Answer:

a)This solution matches with the original equation and its solution

b)This solution matches with the original equation and its solution

c)This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

d)This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

Step-by-step explanation:

i) Which scenarios can be solved by 1.5x +  2.25 = 12.75. Select all that apply and note the given solution.

therefore 1.5x = 10.5   therefore x  = 7

a) let the number be x

   therefore if \frac{3}{2} x + \frac{9}{4}  = \frac{51}{4}  \Rightarrow  1.5x + 2.25 = 12.75  then the number x = 7.

 This solution matches with the original equation and its solution

b.) If a taxi driver charges a flat fee of $2.25 and $1.5 per mile, where the

     number of mile = x, then the number of miles Juan can ride the taxi for

     $12.75 is x = 7.

This solution matches with the original equation and its solution

c)if nine quarters of a number, say x, increased by three halves is fifty one

   quarters, the number is x = 5,

   \frac{9}{4} x + \frac{3}{2}  = \frac{51}{4}  \Rightarrow  9x = 51 - 6 = 45 \therefore x = 5

This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

d.)   If a taxi driver charges a flat fee of $1.5 and $2.25 per mile, where the

     number of mile = x, then the number of miles Juan can ride the taxi for

     $12.75 is x = 5.

2.25x + 1.5  = 12.75  \Rightarrow  9x = 51 - 6 = 45 \therefore x = 5

This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

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Answer:

Step-by-step explanation:

B.28.1

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