I don’t think we should because we all have our one choices that we should achieved and we should show
Complete Question:
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?
Answer:
a) 51.2 msec. b) 5.12 msec
Explanation:
If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:
The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:
a) BW = 1 Mbps = 10⁶ bps
⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec
b) BW = 10 Mbps = 10⁷ bps
⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
D. Make a decision about which colleges to attend that night.
Hi, you've asked an incomplete question. However, I inferred you want to know the type of accounting activity involved in this process.
Answer:
<u>CALCULATING</u>
Explanation:
The process of imposing a 10% interest rate of course would require <em>calculating </em>how much cash value is to be deducted from the "new salary loan" of the respective accounts in the "BPI Family Bank".
This process in accounting often involves computing the individual loan amount multiplied by the interest percentage. For example, a 10% interest rate on a salary loan of $2000 would be 
= $200
