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ss7ja [257]
3 years ago
11

You are to take a multiple-choice exam consisting of 64 questions with 2 possible responses to each question. Suppose that you h

ave not studied and so must guess (select one of the two answers in a completely random fashion) on each question. Let x represent the number of correct responses on the test.
a. what kind of probability does x have?
b. What is your expected score on the exam?
c. Compare the variance and standard deviation of x.
d. based on your answers to parts b and c, is it likely that you would score over 50 on this exam?
Mathematics
1 answer:
Sever21 [200]3 years ago
3 0

Answer:

a) Binomial distribution.

b) Expected value = 32

c) Variance = 16

Standard deviation = 4

d) Getting a score of over 50 is not likely.

Step-by-step explanation:

Probability of getting a question right = (1/2) = 0.5

Probabilty of NOT getting a question right = 1 - 0.5 = 0.5

a) This kind of probability distribution approximates the binomial distribution the most. To solve for the probability of getting any number of questions correctly, the binomial distribution formula would give the required answer.

b) Expected score = mean = np = 64×0.5 = 32

c) Variance = np(1 - p) = 64 × 0.5 × 0.5 = 16

Standard deviation = √(variance) = √16 = 4

d) The mean score = 32.

Standard deviation = 4.

To score over 50, is at least 2 standard deviations away. And it is known that about 95% of the distribution lies between -2 and +2 standard deviations from the mean.

So, a score of over 50 is really not very likely.

Hope this Helps!!!

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There is a triangle with a perimeter of 63 cm, one side of which is 21 cm. Also, one of the medians is perpendicular to one of t
NemiM [27]

Answer:

21cm; 28cm; 14cm

Step-by-step explanation:

There is no info in the problem/s  text which one of the triangle's  side is 21 cm. That is why we have to try all possible variants.

Let the triangle is ABC . Let the AK is the angle A bisector and BM is median.

Let O is AK and BM cross point.

Have a look to triangle ABM.  AO is the bisector and AOB=AOM=90 degrees (means that AO is as bisector as altitude)

=> triangle ABM is isosceles => AB=AM  (1)

1. Let AC=21   So AM=21/2=10.5 cm

So AB=10.5 cm as well.  So BC= P-AB-AC=63-21-10.5=31.5 cm

Such triangle doesn' t exist ( is impossible), because the triangle's inequality doesn't fulfill.  AB+AC>BC ( We have 21+10.5=31.5 => AB+AC=BC)

2. Let AB=21 So AM=21 and AC=42 .So  BC= P-AB-AC=63-21-42=0 cm- such triangle doesn't exist.

3. Finally let BC=21 cm. So AB+AC= 63-21=42 cm

We know (1) that AB=AM so AC=2*AB.  So AB+AC=AB+2*AB=3*AB

=>3*AB=42=> AB=14 cm => AC=2*14=28 cm.

Let check if this triangle exists ( if the triangle's inequality fulfills).

BC+AB>AC    21+14>28 - correct=> the triangle with the sides' length 21cm,14 cm, 28cm exists.

This variant is the only possible solution of the given problem.

6 0
3 years ago
A total of 511 tickets were sold for the school play. They were either adult tickets or student tickets. There were 61 more stud
Marina86 [1]

Answer:

255

Step-by-step explanation:

EXPLANATION We are looking for the number of adult tickets sold. number of adult tickets sold =x We are given that there were 61 more student tickets sold than adult tickets. number of student tickets sold =+x61 The total number of tickets sold was 511.

5 0
3 years ago
This is a polygon. I can’t find the missing angle ?
siniylev [52]
This is a lot of calculation.

So we know that the sum of angles for any heptagon is 900, because heptagon can be divided into five non-overlapping triangles and sum of angles of each triangle is 180.

Now you just add up all angles and simplify the equation:

900 = (6x - 8) + 120 + (7x - 64) + (5x - 4) + 135 + (3x + 31) + (4x + 15)

900 = <span>25x + 225

Now it's just regular algebra equation. You can solve for x:

675 = 25x

x = </span>27

So the value of x is 27
3 0
3 years ago
The scale on a model railroad train set is 3.5 millimeters to 1 foot. If the length of a model car in the set is 150 millimeters
Vera_Pavlovna [14]

Answer:

The approximate length of the actual car is <u>43 feet</u>.

Step-by-step explanation:

Given:

The scale on a model railroad train set is 3.5 millimeters to 1 foot. If the length of a model car in the set is 150 millimeters.

Now, to find the approximate length of the actual car.

Let the actual length of the car is x.

The length of a model car in the set is 150 millimeters.

As, given the scale on a model railroad train set is 3.5 millimeters to 1 foot.

<em>So, 3.5 millimeters equivalent to 1 foot.</em>

<em>Thus, 150 millimeters to </em>x<em>.</em>

Now, to get the actual length of the car by using cross multiplication method:

\frac{3.5}{1} =\frac{150}{x}

<em>By using cross multiplying we get:</em>

3.5x=150

<em>Dividing both sides by 3.5 we get:</em>

x=42.85\ feet.

<em><u>The approximate length of the actual car = 43 feet.</u></em>

Therefore, the approximate length of the actual car is 43 feet.

3 0
3 years ago
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The graph of an even function contains the point (3,-5). Which point must also be on the graph of the function?
Paul [167]

An even function is symmetrical about the y-axis. The mirror image of the point across the y-axis will also be on the graph. That point is found by changing the sign of the x-coordinate: (-3, -5).

3 0
4 years ago
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