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SIZIF [17.4K]
4 years ago
7

The graph of an even function contains the point (3,-5). Which point must also be on the graph of the function?

Mathematics
1 answer:
Paul [167]4 years ago
3 0

An even function is symmetrical about the y-axis. The mirror image of the point across the y-axis will also be on the graph. That point is found by changing the sign of the x-coordinate: (-3, -5).

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If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?
Rufina [12.5K]
x is in quadrant I, so 0, which means 0, so \dfrac x2 belongs to the same quadrant.

Now,

\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}

Since \sin x=\dfrac5{13}, it follows that

\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}

Since x belongs to the first quadrant, you take the positive root (\cos x>0 for x in quadrant I). Then

\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}

\tan x is also positive for x in quadrant I, so you take the positive root again. You're left with

\tan\dfrac x2=\dfrac15
4 0
3 years ago
George studied 3/4 hour on monday and 7/8 hour on tuesday. how long did he study altogether on both days?
pentagon [3]
\dfrac{3}{4}+\dfrac{7}{8}=\dfrac{3\cdot2}{4\cdot2}+\dfrac{7}{8}=\dfrac{6}{8}+\dfrac{7}{8}=\dfrac{6+7}{8}=\dfrac{13}{8}=\dfrac{8+5}{8}=\dfrac{8}{8}+\dfrac{5}{8}=1\dfrac{5}{8}\\\\Answer:\boxed{1\frac{5}{8}\ hour.}
5 0
3 years ago
Solve for y.<br><br> pls help
dybincka [34]

Answer:

y=  -6

Step-by-step explanation:

8 0
3 years ago
What is 5 cm to km? is it 0,00005? if im wrong please correct me because tomorrow i have exam
astra-53 [7]
It's 0.00005 so yeah you're correct
3 0
3 years ago
Read 2 more answers
A craftsman makes a circular table with a radius of 55
Rudik [331]

Answer:

Hey mate here is your answer...

Step-by-step explanation:

smaller circular table to be made

with a diameter only half as big... and diameter of big table is (2*55)= 110cm.... So half diameter of big is (110/2)= 55cm

therefore, diameter of smaller table is 55cm and radius of it's (55/2)= 27.5cm

circumference of circle = 2πr

= 2*3.14*27.5

= 172.7 cm = 27.5cm

hope it helps you ❣️

7 0
2 years ago
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