Question

The options are 0.106,0.63,0.51,0.53

Answer 1

Call $n$ the number of responses.

$P(n \ \textless \ = 2) = P(n=0) + P(n=1) + P(n=2)$

Each of those probabilities will be the frequency of occurrence of the particular event.  We get zero responses 20 out of 200 times, 1 response 30 out of 200, and 2 responses 56 out of 200 times.  So

$P(n \le 2) = \dfrac{20}{200} + \dfrac{30}{200} + \dfrac{56}{200} = \dfrac{20+30+56}{200} = \dfrac{106}{200} = 53\%$

We see we could have just said 20+30+56=106 of the 200 editorials got zero, one or two responses, so the probability is 106/200.

Answer 2

That would be  (20+30+56)/200  =   106/200   = 53/100 Answer